Chapter 13.3, Problem 49SSC

Interpretation Introduction

Interpretation: A balanced chemical equation needs to be written for the given reaction of ethene and oxygen to form carbon dioxide and water.

Concept introduction: To write a balanced chemical, the number of atoms of a particular element present at both sides of equations should be the same.

Answer to Problem 49SSC

  $\begin{array}{l}{\text{C}}_2{\text{H}}_4+3{\text{O}}_2\to 2{\text{H}}_2\text{O}+2\text{C}{\text{O}}_2\end{array}$

  $\begin{array}{c}\text{M}\text{o}\text{l}\text{a}\text{r}\text{r}\text{a}\text{t}\text{i}\text{o}\text{s}1:31:1\end{array}$

Explanation of Solution

The balanced chemical equation when ethene reacts with oxygen is given by:

  ${\text{C}}_2{\text{H}}_4+3{\text{O}}_2\to 2{\text{H}}_2\text{O}+2\text{C}{\text{O}}_2$

  $\begin{array}{c}\text{M}\text{o}\text{l}\text{e}\text{r}\text{a}\text{t}\text{i}\text{o}\text{o}\text{n}\text{l}\text{e}\text{f}\text{t}\text{h}\text{a}\text{n}\text{d}\text{s}\text{i}\text{d}\text{e}=1:3\end{array}$

  $\begin{array}{c}\text{M}\text{o}\text{l}\text{e}\text{r}\text{a}\text{t}\text{i}\text{o}\text{o}\text{n}\text{r}\text{i}\text{g}\text{h}\text{t}\text{h}\text{a}\text{n}\text{d}\text{s}\text{i}\text{d}\text{e}=2:2\end{array}$

               $\begin{array}{c}=1:1\end{array}$

Conclusion

  $\begin{array}{c}\text{M}\text{o}\text{l}\text{e}\text{r}\text{a}\text{t}\text{i}\text{o}\text{o}\text{f}{\text{C}}_2{\text{H}}_4\text{a}\text{n}\text{d}{\text{O}}_2=1:3\end{array}$

  $\begin{array}{c}\text{M}\text{o}\text{l}\text{e}\text{r}\text{a}\text{t}\text{i}\text{o}\text{o}\text{f}{\text{H}}_2\text{O}\text{a}\text{n}\text{d}\text{C}{\text{O}}_2=1:1\end{array}$