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a.
To estimate : What was the initial velocity of the car.
a.
![Check Mark](/static/check-mark.png)
Answer to Problem 36E
The initial velocity is zero.
Explanation of Solution
Given information:
The graph shows the position function of a car. Use the shape of the graph to explain.
Calculation :
The velocity of a car at point
Since, the body started from rest. Therefore, the initial velocity is zero.
Hence,
The initial velocity is zero.
b.
To estimate : The car was going faster at B or at C.
b.
![Check Mark](/static/check-mark.png)
Answer to Problem 36E
The car was going faster at point C.
Explanation of Solution
Given information:
The graph shows the position function of a car. Use the shape of the graph to explain.
Calculation :
The velocity of a car at point
Since, the slope of the tangent at point C is greater than the slope of tangent at B. Therefore, the card was going faster at C
Hence,
The car was going faster at point C.
c.
To estimate : The car was slowing down or speeding up at point A, B and C.
c.
![Check Mark](/static/check-mark.png)
Answer to Problem 36E
The car was speeding up at A, slowing down at B and again speeding up at C.
Explanation of Solution
Given information:
The graph shows the position function of a car. Use the shape of the graph to explain.
Calculation :
The velocity of a car at point
Since, the slope of the tangent at point A is greater, therefore the car was speeding up at point A.
The slope at point B is smaller, therefore the car was slowing down at point B and again the slope at point C is greater, therefore the car again speed up at point C.
Hence,
The car was speeding up at A, slowing down at B and again speeding up at C.
d.
To estimate : What happened between point D and E.
d.
![Check Mark](/static/check-mark.png)
Answer to Problem 36E
The velocity of the car was constant between D and E.
Explanation of Solution
Given information:
The graph shows the position function of a car. Use the shape of the graph to explain.
Calculation :
The velocity of a car at point
Since, the slope between D and E is zero. Therefore, the velocity of the car was constant between D and E.
Hence,
The velocity of the car was constant between D and E.
Chapter 13 Solutions
Precalculus: Mathematics for Calculus - 6th Edition
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