Explanation Given Information: The equation of the parabola x = − ( y + 3 ) 2 + 2 . Consider the equation x = − ( y + 3 ) 2 + 2 . The parabola having equation x = a ( y − k ) 2 + h will have horizontal axis of symmetry. So the provided equation has horizontal axis of symmetry. Now the parabola having equation of the form x = a ( y − k ) 2 + h , then if a > 0 the parabola will open right and if a < 0 parabola opens left. So, rewrite the provided equation as x = − 1 ( y + 3 ) 2 + 2 and compare to find a = − 1 . Therefore, as a < 0 the parabola will open left. Now consider the provided equation x = − 1 ( y + 3 ) 2 + 2 to make a required table to draw a graph, For y = − 2 , x = − ( − 2 + 3 ) 2 + 2 = − 1 + 2 = 1 Therefore, the coordinate is ( 1 , − 2 ) . For y = − 1 , x = − ( − 1 + 3 ) 2 + 2 = − 4 + 2 = − 2 Therefore, the coordinate is ( − 1 , − 2 ) . For y = 0 . x = − ( 0 + 3 ) 2 + 2 = − 9 + 2 = − 7 Therefore, the coordinate is ( − 7 , 0 )

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ISBN: 9781266148941

Author: Miller

Publisher: MCG CUSTOM

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Chapter 13.2, Problem 38PE

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The parabola x=−(y+3)2+2 has axis vertical or horizontal axis of symmetry and then whether it opens upward, downward, left or right.

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Chapter 13.2, Problem 37PE

Chapter 13.2, Problem 39PE

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Ch. 13.1 - Find the distance between the points ( − 4 , − 2 )...Ch. 13.1 - Prob. 2SP Ch. 13.1 - Prob. 3SP Ch. 13.1 - Prob. 4SP Ch. 13.1 - Prob. 5SP Ch. 13.1 - Prob. 6SP Ch. 13.1 - Prob. 7SP Ch. 13.1 - Prob. 8SP Ch. 13.1 - Prob. 1PE Ch. 13.1 - Prob. 2PE

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The parabola x = − ( y + 3 ) 2 + 2 has axis vertical or horizontal axis of symmetry and then whether it opens upward, downward, left or right.

Solution Summary: The author explains that the parabola x=-(y+3)2+2 has a vertical or horizontal axis of symmetry and will open upward, downward, left

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The parabola x=−(y+3)2+2 has axis vertical or horizontal axis of symmetry and then whether it opens upward, downward, left or right.

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Chapter 13 Solutions