Explanation Given information: The maximum height where the ball rises from earth ( h e ) is 60 m . The acceleration of gravity on the moon is 0.165 times that on earth. Calculation: Show the free body diagram of the ball moving to earth trajectory and moon trajectory as in Figure (1). The expression for calculating the initial kinetic energy ( T 1 ) as follows; T 1 = 1 2 m v 2 The expression for calculating the final kinetic energy ( T 2 ) as follows; T 2 = 1 2 m v H 2 The expression for calculating the work done ( U 1 − 2 ) e on earth as follows; ( U 1 − 2 ) e = − m g e h e The expression for calculating the work done ( U 1 − 2 ) m on moon as follows; ( U 1 − 2 ) m = − m g e h m Use work and energy principle which states that kinetic energy of the particle at a displaced point can be obtained by adding the initial kinetic energy and the work done on the particle during its displacement. The expression for the principle of work and energy for the earth is as follows; T 1 + U 1 − 2 = T 2 Substitute 1 2 m v 2 for T 1 , − m g e h e for ( U 1 − 2 ) e , and 1 2 m v H 2 for T 2

VEC MECH 180-DAT EBOOK ACCESS(STAT+DYNA)

12th Edition

ISBN: 9781260916942

Author: BEER

Publisher: MCG

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Chapter 13.1, Problem 13.38P

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Find the height (hm) of same golf ball travel on the moon.

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Chapter 13.1, Problem 13.37P

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Chapter 13 Solutions

VEC MECH 180-DAT EBOOK ACCESS(STAT+DYNA)

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Find the height ( h m ) of same golf ball travel on the moon.

Solution Summary: The author shows the free body diagram of the ball moving to earth trajectory and moon trajectory as in Figure (1).

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