Concept explainers
(a)
To make: a boxplot of the given data
(a)
Answer to Problem 94E
Explanation of Solution
Given:
Calculation:
Sort the data values:
3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 5, 5, 5, 5, 5, 6, 6, 6, 7, 7, 7, 7, 8, 8, 9, 9, 9,10,10, 10, 10, 11, 11, 11, 11, 12, 13, 15, 15, 15, 17,20,21,21,27,31, 34,55
Since the number of data values is odd, the
MEDIAN = 8
The first quartile is the median of all data values below the median. Since the data set contains 25 values below the median, the first quartile is then the 13th data value.
The third quartile is the median of all data values above the median. Since the data set contains 12 values above the median, the third quartile is then the 39th data value.
Outliers are observations that are more than 1.5 times the IQR above Q3 or below Ql. The
The minimum is 3 and the maximum is 55. We then note that 27, 31, 34 and 55 are outliers.
Create a boxplot
The outliers are represented by an X. The box has boundaries the
Conclusion:
Therefore, a boxplot of the given data is drawn.
(b)
To find: to summarize the distribution which one is used
(b)
Answer to Problem 94E
It is best to summarize the distribution by using the median and the IQR
Explanation of Solution
In exercise 94a, we found that the data contains 4 outliers.
It is best to summarize the distribution by using the median and the IQR, because they are not influenced by theoutliers, while the mean and the standard deviation are influenced by the outliers.
Chapter 1 Solutions
The Practice of Statistics for AP - 4th Edition
Additional Math Textbook Solutions
Intro Stats, Books a la Carte Edition (5th Edition)
Elementary Statistics (13th Edition)
Elementary Statistics: Picturing the World (7th Edition)
A First Course in Probability (10th Edition)
Algebra and Trigonometry (6th Edition)
College Algebra (7th Edition)
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