The Practice of Statistics for AP - 4th Edition
The Practice of Statistics for AP - 4th Edition
4th Edition
ISBN: 9781429245593
Author: Starnes, Daren S., Yates, Daniel S., Moore, David S.
Publisher: Macmillan Higher Education
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Chapter 1, Problem 5CRE
To determine

whether there is an association between Facebook use and age

Expert Solution & Answer
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Answer to Problem 5CRE

There exist some association between Facebook users and age

Explanation of Solution

Calculation:

To know about the association between Facebook users and age, calculate the percentages for each of type of the students. The table containing the percentages is given as below.

    Facebook user
    ageyesno
    Younger7282×100=95.12%482×100=4.88%
    Middle4970×100=70%2170×100=30%
    older2167×100=31.34%4667×100=68.66%

On seeing the above table, it is clear that as the age increases the number of user decreases.

Hence, there exist some association between Facebook users and age

Now, make the graph of the provided table of the problem by using MINITAB as below.

  The Practice of Statistics for AP - 4th Edition, Chapter 1, Problem 5CRE , additional homework tip  1

Firstly write down the whole data into MINITAB. The screenshot is given as below.

  The Practice of Statistics for AP - 4th Edition, Chapter 1, Problem 5CRE , additional homework tip  2

Now, click on Graph menu and then select the bar chart option from the dropdown. After this a new dialog box will open. In this, firstly select the option of values from a table, and then select the cluster option under two-way table option and then click on OK button. The screenshot is given as below.

  The Practice of Statistics for AP - 4th Edition, Chapter 1, Problem 5CRE , additional homework tip  3

After this, another dialog box will open. In this, select yes and no responses in graph variableoption and select age in row label option and finally select the option of rows are outermost categories and columns are innermost. The screenshot is given as below.

Finally, click on OK button to have the desired graph of the whole process

The graph is given as below.

  The Practice of Statistics for AP - 4th Edition, Chapter 1, Problem 5CRE , additional homework tip  4

On seeing the above graph, it is clear that as the age increases the number of user decreases

Hence, there exist some association between Facebook users and age

Conclusion:

Therefore, there exist some association between Facebook users and age

Chapter 1 Solutions

The Practice of Statistics for AP - 4th Edition

Ch. 1.1 - Prob. 16ECh. 1.1 - Prob. 17ECh. 1.1 - Prob. 18ECh. 1.1 - Prob. 19ECh. 1.1 - Prob. 20ECh. 1.1 - Prob. 21ECh. 1.1 - Prob. 22ECh. 1.1 - Prob. 23ECh. 1.1 - Prob. 24ECh. 1.1 - Prob. 25ECh. 1.1 - Prob. 26ECh. 1.1 - Prob. 27ECh. 1.1 - Prob. 28ECh. 1.1 - Prob. 29ECh. 1.1 - Prob. 30ECh. 1.1 - Prob. 31ECh. 1.1 - Prob. 32ECh. 1.1 - Prob. 33ECh. 1.1 - Prob. 34ECh. 1.1 - Prob. 35ECh. 1.1 - Prob. 36ECh. 1.2 - Prob. 1.1CYUCh. 1.2 - Prob. 1.2CYUCh. 1.2 - Prob. 1.3CYUCh. 1.2 - Prob. 1.4CYUCh. 1.2 - Prob. 2.1CYUCh. 1.2 - Prob. 2.2CYUCh. 1.2 - Prob. 2.3CYUCh. 1.2 - Prob. 2.4CYUCh. 1.2 - Prob. 3.1CYUCh. 1.2 - Prob. 3.2CYUCh. 1.2 - Prob. 4.1CYUCh. 1.2 - Prob. 4.2CYUCh. 1.2 - Prob. 4.3CYUCh. 1.2 - Prob. 4.4CYUCh. 1.2 - Prob. 37ECh. 1.2 - Prob. 38ECh. 1.2 - Prob. 39ECh. 1.2 - Prob. 40ECh. 1.2 - Prob. 41ECh. 1.2 - Prob. 42ECh. 1.2 - Prob. 43ECh. 1.2 - Prob. 44ECh. 1.2 - Prob. 45ECh. 1.2 - Prob. 46ECh. 1.2 - Prob. 47ECh. 1.2 - Prob. 48ECh. 1.2 - Prob. 49ECh. 1.2 - Prob. 50ECh. 1.2 - Prob. 51ECh. 1.2 - Prob. 52ECh. 1.2 - Prob. 53ECh. 1.2 - Prob. 54ECh. 1.2 - Prob. 55ECh. 1.2 - Prob. 56ECh. 1.2 - Prob. 57ECh. 1.2 - Prob. 58ECh. 1.2 - Prob. 59ECh. 1.2 - Prob. 60ECh. 1.2 - Prob. 61ECh. 1.2 - Prob. 62ECh. 1.2 - Prob. 63ECh. 1.2 - Prob. 64ECh. 1.2 - Prob. 65ECh. 1.2 - Prob. 66ECh. 1.2 - Prob. 67ECh. 1.2 - Prob. 68ECh. 1.2 - Prob. 69ECh. 1.2 - Prob. 70ECh. 1.2 - Prob. 71ECh. 1.2 - Prob. 72ECh. 1.2 - Prob. 73ECh. 1.2 - Prob. 74ECh. 1.2 - Prob. 75ECh. 1.2 - Prob. 76ECh. 1.2 - Prob. 77ECh. 1.2 - Prob. 78ECh. 1.3 - Prob. 1.1CYUCh. 1.3 - Prob. 1.2CYUCh. 1.3 - Prob. 1.3CYUCh. 1.3 - Prob. 1.4CYUCh. 1.3 - Prob. 2.1CYUCh. 1.3 - Prob. 2.2CYUCh. 1.3 - Prob. 2.3CYUCh. 1.3 - Prob. 2.4CYUCh. 1.3 - Prob. 3.1CYUCh. 1.3 - Prob. 3.2CYUCh. 1.3 - Prob. 3.3CYUCh. 1.3 - Prob. 3.4CYUCh. 1.3 - Prob. 79ECh. 1.3 - Prob. 80ECh. 1.3 - Prob. 81ECh. 1.3 - Prob. 82ECh. 1.3 - Prob. 83ECh. 1.3 - Prob. 84ECh. 1.3 - Prob. 85ECh. 1.3 - Prob. 86ECh. 1.3 - Prob. 87ECh. 1.3 - Prob. 88ECh. 1.3 - Prob. 89ECh. 1.3 - Prob. 90ECh. 1.3 - Prob. 91ECh. 1.3 - Prob. 92ECh. 1.3 - Prob. 93ECh. 1.3 - Prob. 94ECh. 1.3 - Prob. 95ECh. 1.3 - Prob. 96ECh. 1.3 - Prob. 97ECh. 1.3 - Prob. 98ECh. 1.3 - Prob. 99ECh. 1.3 - Prob. 100ECh. 1.3 - Prob. 101ECh. 1.3 - Prob. 102ECh. 1.3 - Prob. 103ECh. 1.3 - Prob. 104ECh. 1.3 - Prob. 105ECh. 1.3 - Prob. 106ECh. 1.3 - Prob. 107ECh. 1.3 - Prob. 108ECh. 1.3 - Prob. 109ECh. 1.3 - Prob. 110ECh. 1.3 - Prob. 111ECh. 1.3 - Prob. 112ECh. 1.3 - Prob. 113ECh. 1 - Prob. 1CYUCh. 1 - Prob. 2CYUCh. 1 - Prob. 1ECh. 1 - Prob. 2ECh. 1 - Prob. 3ECh. 1 - Prob. 4ECh. 1 - Prob. 5ECh. 1 - Prob. 6ECh. 1 - Prob. 7ECh. 1 - Prob. 8ECh. 1 - Prob. 1CRECh. 1 - Prob. 2CRECh. 1 - Prob. 3CRECh. 1 - Prob. 4CRECh. 1 - Prob. 5CRECh. 1 - Prob. 6CRECh. 1 - Prob. 7CRECh. 1 - Prob. 8CRECh. 1 - Prob. 9CRECh. 1 - Prob. 10CRECh. 1 - Prob. 1PTCh. 1 - Prob. 2PTCh. 1 - Prob. 3PTCh. 1 - Prob. 4PTCh. 1 - Prob. 5PTCh. 1 - Prob. 6PTCh. 1 - Prob. 7PTCh. 1 - Prob. 8PTCh. 1 - Prob. 9PTCh. 1 - Prob. 10PTCh. 1 - Prob. 11PTCh. 1 - Prob. 12PTCh. 1 - Prob. 13PTCh. 1 - Prob. 14PTCh. 1 - Prob. 15PT
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