The equilibrium constant (Kc) for this reaction is 5.0 at a given temperature. CO ( g ) + H 2 O ( g ) ⇌ CO 2 ( g ) + H 2 ( g ) (a) On analysis, an equilibrium mixture of the substances present at the given temperature was found to contain 0.20 mol of CO, 0.30 mol of water vapor, and 0.90 mol of H 2 in a liter. How many moles of CO 2 were there in the equilibrium mixture? (b) Maintaining the same temperature, additional H 2 was added to the system, and some water vapor was removed by drying. A new equilibrium mixture was thereby established containing 0.40 mol of CO, 0.30 mol of water vapor, and 1.2 mol of H 2 in a liter. How many moles of CO 2 were in the new equilibrium mixture? Compare this with the quantity in part (a), and discuss whether the second value is reasonable. Explain how it is possible for the water vapor concentration to be the same in the two equilibrium solutions even though some vapor was removed before the second equilibrium was established.
The equilibrium constant (Kc) for this reaction is 5.0 at a given temperature. CO ( g ) + H 2 O ( g ) ⇌ CO 2 ( g ) + H 2 ( g ) (a) On analysis, an equilibrium mixture of the substances present at the given temperature was found to contain 0.20 mol of CO, 0.30 mol of water vapor, and 0.90 mol of H 2 in a liter. How many moles of CO 2 were there in the equilibrium mixture? (b) Maintaining the same temperature, additional H 2 was added to the system, and some water vapor was removed by drying. A new equilibrium mixture was thereby established containing 0.40 mol of CO, 0.30 mol of water vapor, and 1.2 mol of H 2 in a liter. How many moles of CO 2 were in the new equilibrium mixture? Compare this with the quantity in part (a), and discuss whether the second value is reasonable. Explain how it is possible for the water vapor concentration to be the same in the two equilibrium solutions even though some vapor was removed before the second equilibrium was established.
The equilibrium constant (Kc) for this reaction is 5.0 at a given temperature.
CO
(
g
)
+
H
2
O
(
g
)
⇌
CO
2
(
g
)
+
H
2
(
g
)
(a) On analysis, an equilibrium mixture of the substances present at the given temperature was found to contain 0.20 mol of CO, 0.30 mol of water vapor, and 0.90 mol of H2 in a liter. How many moles of CO2 were there in the equilibrium mixture?
(b) Maintaining the same temperature, additional H2 was added to the system, and some water vapor was removed by drying. A new equilibrium mixture was thereby established containing 0.40 mol of CO, 0.30 mol of water vapor, and 1.2 mol of H2 in a liter. How many moles of CO2 were in the new equilibrium mixture? Compare this with the quantity in part (a), and discuss whether the second value is reasonable. Explain how it is possible for the water vapor concentration to be the same in the two equilibrium solutions even though some vapor was removed before the second equilibrium was established.
Choose the Lewis structure for the compound below:
H2CCHOCH2CH(CH3)2
HH
H
:d
H
H
H C.
Η
H
H
HH
H
H
H
H.
H
H
H
HH
H
H
H
H
H-
H
H
H
C-H
H
H
HHHH
Each of the highlighted carbon atoms
is connected to
hydrogen atoms.
く
Complete the reaction in the drawing area below by adding the major products to the right-hand side.
If there won't be any products, because nothing will happen under these reaction conditions, check the box under the drawing area
instead.
Note: if the products contain one or more pairs of enantiomers, don't worry about drawing each enantiomer with dash and wedge
bonds. Just draw one molecule to represent each pair of enantiomers, using line bonds at the chiral center.
More...
No reaction.
Explanation
Check
O
+
G
1. Na O Me
Click and drag to start
drawing a structure.
2. H
+
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000
Ar
P
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell