Introductory Chemistry, Books a la Carte Plus MasteringChemistry with eText -- Access Card Package (5th Edition)
5th Edition
ISBN: 9780321934604
Author: Nivaldo J. Tro
Publisher: PEARSON
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Chapter 13, Problem 75E
Interpretation Introduction
Interpretation: The volume required for
Concept Introduction:
Molarity of a substance is defined as the number of moles of solute dissolved per liter of solution.
The relation between molarity
A number of moles are equal to the ratio of the mass of substance and molecular mass of a substance.
The relation between mass
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need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Please correct answer and don't used hand raiting
need help please and thanks dont understand a-b
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal energy
Divide the…
Chapter 13 Solutions
Introductory Chemistry, Books a la Carte Plus MasteringChemistry with eText -- Access Card Package (5th Edition)
Ch. 13 - Which compound forms an electroIyte solution When...Ch. 13 - A solution is saturated in O2 gas and KNO3 at room...Ch. 13 -
Q3. What is the mass percent concentration of a...Ch. 13 - Prob. 4SAQCh. 13 - What mass of glucose (C6H12O6) is contained in...Ch. 13 - What is the molar concentration of potassium ions...Ch. 13 - Prob. 8SAQCh. 13 - Potassium iodide reacts with lead(ll) nitrate in...Ch. 13 - Prob. 10SAQCh. 13 -
Q11. Calculate the freezing point of 1.30 m...
Ch. 13 - What mass of ethylene glycol (C2H6O6) must be...Ch. 13 - Prob. 1ECh. 13 - Prob. 2ECh. 13 - Prob. 3ECh. 13 - Explain what like dissolves like means.Ch. 13 - What is solubility?Ch. 13 - Describe what happens when additional solute is...Ch. 13 -
7. Explain the difference between a strong...Ch. 13 -
8. How does gas solubility depend on...Ch. 13 - Prob. 9ECh. 13 - Prob. 10ECh. 13 -
11. When you heat water on a stove, bubbles form...Ch. 13 - Prob. 12ECh. 13 - How does gas solubility depend on pressure? How...Ch. 13 -
14. What is the difference between a dilute...Ch. 13 -
15. Define the concentration units mass percent...Ch. 13 - Prob. 16ECh. 13 -
17. How does the presence of a nonvolatile solute...Ch. 13 - What are colligative properties?Ch. 13 - Prob. 19ECh. 13 - Prob. 20ECh. 13 -
21. Two shipwreck survivors were rescued from a...Ch. 13 - 22 Why are intravenous fluids always isoosmotic...Ch. 13 - Prob. 23ECh. 13 - Prob. 24ECh. 13 - Identify the solute and solvent in each solution....Ch. 13 - Prob. 26ECh. 13 - Prob. 27ECh. 13 - Prob. 28ECh. 13 - What are the dissolved particles in a solution...Ch. 13 - What are the dissolved particles in a solution...Ch. 13 - A solution contains 35 g of Nacl per 100 g of...Ch. 13 - Prob. 32ECh. 13 - A KNO3 solution containing 45 g of KNO3 per 100 g...Ch. 13 - Prob. 34ECh. 13 - Refer to Figure 13.4 to determine whether each of...Ch. 13 - Prob. 36ECh. 13 - Prob. 38ECh. 13 - Scuba divers breathing air at increased pressure...Ch. 13 - Prob. 40ECh. 13 - Prob. 41ECh. 13 - Prob. 42ECh. 13 - MASS PERCENT The solubility of LiCl is 55 g per...Ch. 13 - A soft drink contains 32 mg of sodium in 309 g of...Ch. 13 - Prob. 45ECh. 13 - Prob. 46ECh. 13 - Prob. 47ECh. 13 - Prob. 48ECh. 13 - Prob. 49ECh. 13 - Prob. 50ECh. 13 - Prob. 51ECh. 13 - Prob. 52ECh. 13 - MASS PERCENT Sodium can be dissolved in mercury to...Ch. 13 - A dioxin-contaminated water source contains 0.085%...Ch. 13 - Prob. 55ECh. 13 - Prob. 56ECh. 13 - Prob. 57ECh. 13 - Prob. 58ECh. 13 - Calculate the molarity of each solution. a. 0.127...Ch. 13 - Prob. 60ECh. 13 - Calculate the molarity of each solution. a. 22.6 g...Ch. 13 - Prob. 62ECh. 13 - 63. A 205-mL sample of ocean water contains 6.8 g...Ch. 13 - Prob. 64ECh. 13 - Prob. 65ECh. 13 - Prob. 66ECh. 13 - Prob. 67ECh. 13 - Prob. 68ECh. 13 - Prob. 69ECh. 13 - Prob. 70ECh. 13 - Calculate the mass of NaCl in a 35-mL sample of a...Ch. 13 - Prob. 72ECh. 13 - Prob. 73ECh. 13 - 74. A laboratory procedure calls for making 500.0...Ch. 13 - Prob. 75ECh. 13 - Prob. 76ECh. 13 - Prob. 77ECh. 13 - Prob. 78ECh. 13 - Prob. 79ECh. 13 - Prob. 80ECh. 13 - Prob. 81ECh. 13 - Prob. 82ECh. 13 - Prob. 83ECh. 13 - 84. Describe how you would make 500.0 mL of a...Ch. 13 - Prob. 85ECh. 13 - Prob. 86ECh. 13 - Prob. 87ECh. 13 - Prob. 88ECh. 13 - 89. Determine the volume of 0.150 M NaOH solution...Ch. 13 - Prob. 90ECh. 13 - Consider the reaction:...Ch. 13 - Prob. 92ECh. 13 - Prob. 93ECh. 13 - 94. A 25.0-mL sample of an unknown solution...Ch. 13 - 95. What is the minimum amount of necessary to...Ch. 13 - Prob. 96ECh. 13 - Prob. 97ECh. 13 - Prob. 98ECh. 13 - MOLALITY, FREEZING POINT DEPRESSION, AND BOILING...Ch. 13 - Prob. 100ECh. 13 - Prob. 101ECh. 13 - Prob. 102ECh. 13 - Prob. 103ECh. 13 - Prob. 104ECh. 13 - Prob. 105ECh. 13 - 106. An ethylene glycol solution contains 21.2 g...Ch. 13 - Prob. 107ECh. 13 - Prob. 108ECh. 13 - Prob. 109ECh. 13 - Prob. 110ECh. 13 - Prob. 111ECh. 13 - Prob. 112ECh. 13 - What is the molarity of an aqueous solution that...Ch. 13 - Prob. 114ECh. 13 - Consider the reaction:...Ch. 13 - Prob. 116ECh. 13 - Prob. 117ECh. 13 - Prob. 118ECh. 13 - Prob. 119ECh. 13 - Prob. 120ECh. 13 - Prob. 121ECh. 13 - A sucrose solution is made using 144 g of sucrose...Ch. 13 - Prob. 123ECh. 13 - Prob. 124ECh. 13 - Prob. 125ECh. 13 - 126. An aqueous solution containing 35.9 g of an...Ch. 13 - Prob. 127ECh. 13 - Prob. 128ECh. 13 - A 125-g sample contains only glucose (C6H12O6) and...Ch. 13 - 130. A 9:1 ethylene glycol (C2H6O2) and propylene...Ch. 13 - Consider the molecular views of osmosis cells. For...Ch. 13 - What is wrong with this molecular view of a sodium...Ch. 13 - Prob. 133ECh. 13 - 134. Hard water refers to a water sample...Ch. 13 - Prob. 135ECh. 13 - Prob. 136ECh. 13 - Prob. 137ECh. 13 - Prob. 138E
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY