
Concept explainers
Interpretation:
The normal freezing point and boiling point of the given solution are to be calculated with the help of mass of solute and volume of solvent.
Concept introduction:
The expression for freezing point depression is given as follows:
Here,
denotes freezing point depression of solute,
denotes Van’t Hoff factor,
denotes the freezing point depression constant
The freezing point of pure solute is represented by
The expression for boiling point elevation is given as follows:
Here, the boiling point of pure solute is represented by
denotes Van’t Hoff factor,
denotes the boiling point elevation constant
The molality of the solution is calculated by the expression as:
Moles of compound can be calculated by the expression:
So, molality can also be calculated by:

Answer to Problem 67QP
Solution:
Explanation of Solution
a)
Since
For
The molar mass of
The normal boiling point and freezing point of water are given as follows:
The molality of the solution is calculated by the expression as follows:
Substitute the required values in the equation given above,
Therefore, the molality of
is
The expression for freezing point depression is given as follows:
Substitute the values of
Hence, the normal freezing point of
is
The expression for boiling point elevation is given as follows:
Substitute the values of
Hence, the normal boiling point of
is
b)
Since
of water is
For urea, the value of
The molar mass of urea is
The normal boiling point and freezing point of water are given as follows:
The molality of the solution can be evaluated as follows:
Substitute the required values in the equation given above.
Therefore, molality of urea is
The expression for freezing point depression is given as follows:
Substitute the values of
Hence, the normal freezing point of urea is
The expression for boiling point elevation is given as follows:
Substitute the values of
Hence, the normal boiling point of urea is
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Chapter 13 Solutions
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