(a) Explanation Given data: Mass of gasoline is 50 g and mass of water is 50 g. Formula used: Write the expression for average density ( ρ ) . ρ avg = m total V total (1) Here, m total is total mass mixture, and V total is volume of mixture. Write the expression for total mass of mixture ( m total ) . m total = m gasoline + m water (2) Here, m gasoline is mass of gasoline, and m water is mass of water. Refer to Table 13.1 in the textbook for the densities of fluids at 1 atm pressure. Substitute 50 g for m gasoline and 50 g for m water in equation (2), m total = 50 g + 50 g = 100 g = 100 × 10 − 3 kg { 1 g = 10 − 3 kg } = 0 .10 kg From Table 13.1, the density of gasoline ( ρ gasoline ) is 680 kg m 3 and density of water ( ρ water ) is 1000 kg m 3 . Write the expression for total volume ( V total ) . V total = V gasoline + V water Modify the equation. V total = m gasoline ρ gasoline + m water ρ water Substitute 50 g for m gasoline , 50 g for m water , 680 kg m 3 for ρ gasoline , and 1000 kg (b) To determine The average density of mixture of 50 cm 3 of gasoline and 50 cm 3 of water.

College Physics: A Strategic Approach (3rd Edition)

3rd Edition

ISBN: 9780321879721

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Density of Solids

The density of a substance refers to how much matter is present in a given amount of space. It is expressed as the ratio of the mass of the substance to its volume.

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Chapter 13, Problem 5P

(a)

To determine

The average density of mixture of 50 g of gasoline and 50 g of water.

(b)

To determine

The average density of mixture of 50 cm3 of gasoline and 50 cm3 of water.

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Chapter 13, Problem 4P

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Chapter 13 Solutions

College Physics: A Strategic Approach (3rd Edition)

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The average density of mixture of 50 g of gasoline and 50 g of water.

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The average density of mixture of 50 g of gasoline and 50 g of water.

The average density of mixture of 50 cm3 of gasoline and 50 cm3 of water.

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Chapter 13 Solutions