Based on a sample of n = 20 , the latest-squares method was used to develop the following prediction line: Y ^ i = 5 + 3 X i . In addition, S YX = 1.0 X ¯ = 2 ∑ i = i n X i − X ¯ 2 = 20 a. Construct a 95 % confidence interval estimate of the population mean response for X = 4. b. Construct a 95 % prediction interval of an individual response for X = 4. c. Compare the result of (a) and (b) with those of problem 13.55 (a) and (b). Which intervals are wider? Why?
Based on a sample of n = 20 , the latest-squares method was used to develop the following prediction line: Y ^ i = 5 + 3 X i . In addition, S YX = 1.0 X ¯ = 2 ∑ i = i n X i − X ¯ 2 = 20 a. Construct a 95 % confidence interval estimate of the population mean response for X = 4. b. Construct a 95 % prediction interval of an individual response for X = 4. c. Compare the result of (a) and (b) with those of problem 13.55 (a) and (b). Which intervals are wider? Why?
Solution Summary: The author calculates a 95% confidence interval estimate of the population mean response for X=4 using the least-squares method.
Based on a sample of
n
=
20
,
the latest-squares method was used to develop the following prediction line:
Y
^
i
=
5
+
3
X
i
.
In addition,
S
YX
=
1.0
X
¯
=
2
∑
i
=
i
n
X
i
−
X
¯
2
=
20
a. Construct a
95
%
confidence interval estimate of the population mean response for
X
=
4.
b. Construct a
95
%
prediction interval of an individual response for
X
=
4.
c. Compare the result of (a) and (b) with those of problem 13.55 (a) and (b). Which intervals are wider? Why?
Definition Definition Number of subjects or observations included in a study. A large sample size typically provides more reliable results and better representation of the population. As sample size and width of confidence interval are inversely related, if the sample size is increased, the width of the confidence interval decreases.
Please could you explain why 0.5 was added to each upper limpit of the intervals.Thanks
28. (a) Under what conditions do we say that two random variables X and Y are
independent?
(b) Demonstrate that if X and Y are independent, then it follows that E(XY) =
E(X)E(Y);
(e) Show by a counter example that the converse of (ii) is not necessarily true.
1. Let X and Y be random variables and suppose that A = F. Prove that
Z XI(A)+YI(A) is a random variable.
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