Chapter 13, Problem 44E

(a)

Interpretation Introduction

Interpretation: The volume of $\text{HCl}$ that is required to neutralize $\text{50}\text{mL}$ of $\text{0}\text{.101}\text{M}\text{Ba}{\left(\text{OH}\right)}_{\text{2}}$ solution.

Concept introduction:
The volume of $\text{HCl}$ required for neutralization of $\text{50}\text{mL}$ of $\text{0}\text{.101}\text{M}\text{Ba}{\left(\text{OH}\right)}_{\text{2}}$ is calculated by the formula,

  $\begin{array}{c}\frac{M_1{V}_1}{n_1}=\frac{M_2{V}_2}{n_2}\\ V_1=\frac{n_1{M}_2{V}_2}{M_1{n}_2}\end{array}$

(b)

Interpretation Introduction

Interpretation: The volume of $\text{0}\text{.125}\text{M}$

${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ required to neutralize $\text{0}\text{.200}\text{g}\text{NaOH}$ .

Concept introduction:
The number of moles is the ratio of given mass of the compound in grams to the molar mass of the compound.
$n=\frac{m}{M}$

(c)

Interpretation Introduction

Interpretation: The molarity of ${\text{BaCl}}_{\text{2}}$ solution if $\text{55}\text{.8}\text{mL}$${\text{BaCl}}_{\text{2}}$ solution is required to precipitate all ${\text{SO}}_4^{2-}$ ion in the solution.

Concept introduction:

Molarity is defined as the ratio of number of moles of solute to the volume of the solution in liters.
The molarity is calculated by the formula,

    $\text{Molarity}=\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}}$

(d)

Interpretation Introduction

Interpretation: The mass of $\text{Ca}{\left(\text{OH}\right)}_2$ present in the solution if $\text{42}\text{.7}\text{mL}$ of $\text{0}\text{.208}\text{M}$

$\text{HCl}$ solution is required to neutralize the $\text{Ca}{\left(\text{OH}\right)}_2$ solution.

Concept introduction: The mass of $\text{Ca}{\left(\text{OH}\right)}_2$ is calculated by the formula,

   $\begin{array}{c}n=\frac{m}{M}\\ m=\left(n\times M\right)\end{array}$

Here,

• $n$ is the number of moles of $\text{Ca}{\left(\text{OH}\right)}_2$ .
• $m$ is the given mass of $\text{Ca}{\left(\text{OH}\right)}_2$ .
• $M$ is the molar mass of $\text{Ca}{\left(\text{OH}\right)}_2$ .