The approximate area of the function f ( x ) = 16 x 2 − x 4 + 2 between x = − 2 and x = 3 by drawing five rectangles and each of height of the left side of the function.

Question

Want to see the full answer?

Answer 1

Question

Chapter 13, Problem 37RE

(a)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by drawing five rectangles and each of height of the left side of the function.

(b)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by using numerical integration.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

A: Tan Latitude / Tan P A = Tan 04° 30'/ Tan 77° 50.3' A= 0.016960 803 S CA named opposite to latitude, except when hour angle between 090° and 270°) B: Tan Declination | Sin P B Tan 052° 42.1'/ Sin 77° 50.3' B = 1.34 2905601 SCB is alway named same as declination) C = A + B = 1.35 9866404 S CC correction, A+/- B: if A and B have same name - add, If different name- subtract) = Tan Azimuth 1/Ccx cos Latitude) Tan Azimuth = 0.737640253 Azimuth = S 36.4° E CAzimuth takes combined name of C correction and Hour Angle - If LHA is between 0° and 180°, it is named "west", if LHA is between 180° and 360° it is named "east" True Azimuth= 143.6° Compass Azimuth = 145.0° Compass Error = 1.4° West Variation 4.0 East Deviation: 5.4 West

Direction: Strictly write in 4 bond paper, because my activity sheet is have 4 spaces. This is actually for maritime. industry course, but I think geometry can do this. use nautical almanac. Sample Calculation (Amplitude- Sun): On 07th May 2006 at Sunset, a vesel in position 10°00'N 0 10°00' W observed the sun bearing 288° by compass. Find the compass error. LMT Sunset 07d 18h 13m (+)00d 00h 40 м LIT: UTC Sunset: 07d 18h 53 m added - since longitude is westerly Declination Co7d 18h): N016° 55.5' d(0.7): (+) 00-6 N016 56.1' Declination Sun: Sin Amplitude Sin Declination (Los Latitude - Sin 016° 56.1'/Cos 10°00' = 0.295780189 Amplitude = WI. 2N (The prefix of amplitude is named easterly if body is rising. and westerly of body is setting. The suffix is named came as declination.) True Bearing: 287.20 Compass Bearing 288.0° Compass Error: 0.8' West

Answer 2

Question

Chapter 13, Problem 37RE

(a)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by drawing five rectangles and each of height of the left side of the function.

(b)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by using numerical integration.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 13, Problem 37RE

(a)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by drawing five rectangles and each of height of the left side of the function.

(b)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by using numerical integration.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 13, Problem 37RE

(a)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by drawing five rectangles and each of height of the left side of the function.

(b)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by using numerical integration.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 13, Problem 37RE

(a)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by drawing five rectangles and each of height of the left side of the function.

(b)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by using numerical integration.

Answer 6

Chapter 13, Problem 37RE

(a)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by drawing five rectangles and each of height of the left side of the function.

Answer 7

Chapter 13, Problem 37RE

(a)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by drawing five rectangles and each of height of the left side of the function.

Answer 8

(b)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by using numerical integration.

Answer 9

(b)

To determine

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by using numerical integration.

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 13.1 - Checkpoint 1 Find an antiderivative for each of...Ch. 13.1 - Checkpoint 2 Find each of the...Ch. 13.1 - Prob. 3CP Ch. 13.1 - Prob. 4CP Ch. 13.1 - Prob. 5CP Ch. 13.1 - Prob. 6CP Ch. 13.1 - Prob. 7CP Ch. 13.1 - Checkpoint 8 The marginal cost at a level of...Ch. 13.1 - 1. What must be true of F(x) and G(x) if both are...Ch. 13.1 - 2. How is the antiderivative of a function related...

The approximate area of the function f ( x ) = 16 x 2 − x 4 + 2 between x = − 2 and x = 3 by drawing five rectangles and each of height of the left side of the function.

Solution Summary: The author calculates the approximate area of the function f(x)=16x

Videos

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by drawing five rectangles and each of height of the left side of the function.

To calculate: The approximate area of the function f(x)=16x2−x4+2 between x=−2 and x=3 by using numerical integration.

Want to see the full answer?

Chapter 13 Solutions