Automotive Technology: A Systems Approach - With Manual and Access
6th Edition
ISBN: 9781305513235
Author: ERJAVEC
Publisher: Cengage
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Chapter 13, Problem 2RQ
How does a torque-to-yield bolt differ from standard bolts?
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Both portions of the rod ABC are made of an aluminum for which E = 70 GPa.
Based on the given information find:
1- deformation at A
2- stress in BC
3- Total strain
4- If v (Poisson ratio is 0.25, find the
lateral deformation of AB
Last 3 student ID+ 300 mm=L2
724
A
P=Last 2 student ID+ 300 KN
24
24
Diameter Last 2 student ID+ 15 mm
Last 3 student ID+ 500 mm=L1
724
C
B
24
Q=Last 2 student ID+ 100 KN
24
Diameter Last 2 student ID+ 40 mm
Q2Two wooden members of uniform cross section are joined by the simple scarf splice shown. Knowing that the
maximum allowable tensile stress in the glued splice is 75 psi, determine (a) the largest load P that can be safely
supported, (b) the corresponding shearing stress in the splice.
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Last 1 student ID+5 inch=W
=9
4
L=Last 1 student ID+8 inch
=12
60°
P'
Q4
The two solid shafts are connected by gears as shown and are made of a steel for which the allowable shearing
stress is 7000 psi. Knowing the diameters of the two shafts are, respectively, dBC
determine the largest torque Tc that can be applied at C.
4
and dEF
dBC=Last 1 student ID+3 inch
dEF=Last 1 student ID+1 inch
7
R=Last 1 Student ID+5 inch
9
R
B
Tc
2.5 in.
E
TF
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Chapter 13 Solutions
Automotive Technology: A Systems Approach - With Manual and Access
Ch. 13 - True or False? Make sure you locate and adhere to...Ch. 13 - How does a torque-to-yield bolt differ from...Ch. 13 - How do seals differ from gaskets?Ch. 13 - Where are thread sealers most often used?Ch. 13 - What are the major differences between aerobic and...Ch. 13 - Which of the following statements is incorrect?...Ch. 13 - True or False? Valve lash is adjusted in many...Ch. 13 - Which of the following statements about the...Ch. 13 - True or False? The computer in most late-model...Ch. 13 - Graphite is. an anaerobic substance an RTV an...
Ch. 13 - Which of the following are considered soft, cut...Ch. 13 - What material is typically not used to form a rear...Ch. 13 - Which of the following statements about preparing...Ch. 13 - On hybrid vehicles, how can you identify the high...Ch. 13 - True or False? Some crankshaft and camshaft timing...Ch. 13 - Prob. 1ASRQCh. 13 - Technician A uses adhesives to hold gaskets in...Ch. 13 - Technician A uses soft gaskets on valve covers....Ch. 13 - Technician A inspects all sealing surfaces for...Ch. 13 - Technician A says that oil pan gaskets are often...Ch. 13 - Prob. 6ASRQCh. 13 - While discussing proper engine break-in:...Ch. 13 - Prob. 8ASRQCh. 13 - Prob. 9ASRQCh. 13 - While selecting the proper RTV for a particular...
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- Procedure: 1- Cartesian system, 2D3D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D ∑Fx=0 ∑Fy=0 ∑Fz=0 ∑Mx=0 ∑My=0 ΣMz=0 2D ΣFx=0 ΣFy=0 ΣMz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of thearrow_forwardProcedure:1- Cartesian system, 2D3D,type of support2- Free body diagram3 - Find the support reactions4- If you find a negativenumber then flip the force5- Find the internal force3D∑Fx=0∑Fy=0∑Fz=0∑Mx=0∑My=0\Sigma Mz=02D\Sigma Fx=0\Sigma Fy=0\Sigma Mz=05- Use method of sectionand cut the elementwhere you want to findthe internal force andkeep either side of thearrow_forwardProcedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forward
- Procedure: 1- Cartesian system, 2(D)/(3)D, type of support 2- Free body diagram 3 - Find the support reactions 4- If you find a negative number then flip the force 5- Find the internal force 3D \sum Fx=0 \sum Fy=0 \sum Fz=0 \sum Mx=0 \sum My=0 \Sigma Mz=0 2D \Sigma Fx=0 \Sigma Fy=0 \Sigma Mz=0 5- Use method of section and cut the element where you want to find the internal force and keep either side of the sectionarrow_forwardFor each system below with transfer function G(s), plot the pole(s) on the s-plane. and indicate whether the system is: (a) "stable" (i.e., a bounded input will always result in a bounded output), (b) "marginally stable," or (c) "unstable" Sketch a rough graph of the time response to a step input. 8 a) G(s) = 5-5 8 b) G(s) = c) G(s) = = s+5 3s + 8 s² - 2s +2 3s +8 d) G(s): = s²+2s+2 3s+8 e) G(s): = s² +9 f) G(s): 8 00 == Sarrow_forwardPlease answer the following question. Include all work and plase explain. Graphs are provided below. "Consider the Mg (Magnesium) - Ni (Nickel) phase diagram shown below. This phase diagram contains two eutectic reactions and two intermediate phases (Mg2Ni and MgNi2). At a temperature of 505oC, determine what the composition of an alloy would need to be to contain a mass fraction of 0.20 Mg and 0.80 Mg2Ni."arrow_forward
- The triangular plate, having a 90∘∘ angle at AA, supports the load PP = 370 lblb as shown in (Figure 1).arrow_forwardDesign a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, ß2 = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. φ 1.236 P2 147.5° 210° 2.138 P1 Figure 1 Xarrow_forwardDesign a 4-bar linkage to carry the body in Figure 1 through the two positions P1 and P2 at the angles shown in the figure. Use analytical synthesis with the free choice values z = 1.075, q= 210°, B₂ = −27° for left side and s = 1.24, y= 74°, ½ = − 40° for right side. 1.236 P2 147.5° 210° P1 Figure 1 2.138 Xarrow_forward
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