
Interpretation:
The reaction when hydrogen chloride reacts with 2-methyl-1,3-butadiene to form 1-chloro-3-methyl-2-butene as a major product via 1,4-addition mechanism and no product formed by 1,2-additon, is to be explained.
Concept introduction:
舧 Electrophiles are electron-deficient species, which has positive or partially positive charge. Lewis acids are electrophiles, which accept electron pair.
舧 Nucleophiles are electron rich species, which has negative or partially negative charge. Lewis bases are nucleophiles, which donate electron pair.
舧 Free radical is an atom, molecule or ion that has an unpaired electron, which makes it highly chemically reactive.
舧 Substitution reaction: A reaction in which one of the hydrogen atoms of a hydrocarbon or a
舧 Elimination reaction: A reaction in which two substituent groups are detached and a double bond is formed is called elimination reaction.
舧 Addition reaction: It is the reaction in which unsaturated bonds are converted to saturated molecules by the addition of molecules.
舧 The reaction in which there is addition of hydrogen molecule is called hydrogenation reaction.
舧
舧 Hydrogenation with platinum as a catalyst is used to convert unsaturated carbohydrates to saturated hydrocarbons
舧 Oxidation of
舧 Ozonolysis helps convert the carbon–carbon double bonds to carbon–oxygen double bond (carbonyl compounds).
舧 Dimethyl sulfide is used as a reducing agent that decomposes the intermediate formed into the carbonyl group.
舧 NBS (nitro-bromo succinimide) is a special reagent used for bromination of allylic carbocations.
舧 Bromine replaces the hydrogen attached to the carbon adjacent to the carbon bearing double bond.
舧 This method of using NBS can produce allylic bromides without bromine reacting with the double bond.
舧 Dehydration of a primary alcohol in the presence of a mineral acid like concentrated sulfuric acid results in the formation of alkene via E2 elimination.
舧 The stability of carbocation:
舧 The 1,2 – addition to a diene is the addition of an electrophile to the carbon designated as 1 and a nucleophile to the carbon designated as 2. The positions of carbons as 1 and 2 are not according to the IUPAC numbering of the molecule, but as a conjugated diene molecule. 1,4-addition results in addition of hydrogen to thee carbon designated as 1 and a halogen to the carbon designated as 4.
舧 The mechanism of 1,2 addition and 1,4-addition of hydro halogenation is given below:

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Chapter 13 Solutions
Organic Chemistry, 12e Study Guide/Student Solutions Manual
- Select the stronger base from each pair of compounds. (a) H₂CNH₂ or EtzN (b) CI or NH2 NH2 (c) .Q or EtzN (d) or (e) N or (f) H or Harrow_forward4. Provide a clear arrow-pushing mechanism for each of the following reactions. Do not skip proton transfers, do not combine steps, and make sure your arrows are clear enough to be interpreted without ambiguity. a. 2. 1. LDA 3. H3O+ HOarrow_forwardb. H3C CH3 H3O+ ✓ H OHarrow_forward
- 2. Provide reagents/conditions to accomplish the following syntheses. More than one step is required in some cases. a. CH3arrow_forwardIdentify and provide an explanation that distinguishes a qualitative and quantitative chemical analysis. Provide examples.arrow_forwardIdentify and provide an explanation of the operational principles behind a Atomic Absorption Spectrometer (AAS). List the steps involved.arrow_forward
- Instructions: Complete the questions in the space provided. Show all your work 1. You are trying to determine the rate law expression for a reaction that you are completing at 25°C. You measure the initial reaction rate and the starting concentrations of the reactions for 4 trials. BrO³¯ (aq) + 5Br¯ (aq) + 6H* (aq) → 3Br₂ (l) + 3H2O (l) Initial rate Trial [BrO3] [H*] [Br] (mol/L) (mol/L) | (mol/L) (mol/L.s) 1 0.10 0.10 0.10 8.0 2 0.20 0.10 0.10 16 3 0.10 0.20 0.10 16 4 0.10 0.10 0.20 32 a. Based on the above data what is the rate law expression? b. Solve for the value of k (make sure to include proper units) 2. The proposed reaction mechanism is as follows: i. ii. BrО¸¯ (aq) + H+ (aq) → HBrO3 (aq) HBrO³ (aq) + H* (aq) → H₂BrO3* (aq) iii. H₂BrO³* (aq) + Br¯ (aq) → Br₂O₂ (aq) + H2O (l) [Fast] [Medium] [Slow] iv. Br₂O₂ (aq) + 4H*(aq) + 4Br(aq) → 3Br₂ (l) + H2O (l) [Fast] Evaluate the validity of this proposed reaction. Justify your answer.arrow_forwardе. Д CH3 D*, D20arrow_forwardC. NaOMe, Br Brarrow_forward
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