Explanation Given: Temperature of interior of the Earth, T E = 4000 ° C Temperature of the interior of the Sun, T S = 15 × 10 6 ° C Formula used: T ( K ) = T ( ° C ) + 273.15 Calculation: The conversion of temperature from Celsius scale to Kelvin is given by, T ( K ) = T ( ° C ) + 273.15 Therefore, for the interior of the Earth, T ( K ) = 4000 ° C + 273.15 = 4273... To determine (b) To determine: The percent error made in each case if a person forgets to change from °C to K

7th Edition

ISBN: 9780321625915

Author: Douglas C. Giancoli

Publisher: PEARSON

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Question

Chapter 13, Problem 22P

To determine

(a) To determine:

The values of the temperatures of the interior of the Earth and the Sun in Kelvin

To determine

(b) To determine:

The percent error made in each case if a person forgets to change from °C to K

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Chapter 13, Problem 21P

Chapter 13, Problem 23P

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* Coulomb's Law Example Three charges are positioned as seen below. Charge 1 is +2.0 μC and charge 2 is +8.0μC, and charge 3 is - 6.0MC. What is the magnitude and the direction of the force on charge 2 due to charges 1 and 3? 93 kq92 F == 2 r13 = 0.090m 91 r12 = 0.12m 92 Coulomb's Constant: k = 8.99x10+9 Nm²/C² ✓

Make sure to draw a Free Body Diagram as well

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(a) To determine: The values of the temperatures of the interior of the Earth and the Sun in Kelvin