With relation to the air outside the balloon, the effect on the temperature, pressure and density of the air inside the balloon when it is heated by a flame

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Answer 1

Question

Chapter 13, Problem 1OQ

To determine

With relation to the air outside the balloon, the effect on the temperature, pressure and density of the air inside the balloon when it is heated by a flame

Expert Solution & Answer

Answer to Problem 1OQ

Solution:

Temperature is higher inside the balloon
Pressure is same inside and outside balloon
Density is lower

Explanation of Solution

A. Temperature is higher inside the balloon. This is the basic principle on which a hot-air balloon works. As the air inside the balloon gets heated by the flame, it rises upwards through the surrounding air, which is colder.

B. Pressure is the same inside and outside the balloon. Otherwise, the balloon would inflate or deflate. The density of air particles is lower because of the high temperature inside the balloon. This should lower the pressure. But because of the higher energy of these particles, they are moving faster and even this smaller quantity ends up exerting the pressure required to balance the outside pressure.

C. Density is lower. Because of the higher temperature of the air, the density is lower.

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The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE DO NOT USE LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!

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The force of the quadriceps (Fq) and force of the patellar tendon (Fp) is identical (i.e., 1000 N each). In the figure below angle in blue is Θ and the in green is half Θ (i.e., Θ/2). A) Calculate the patellar reaction force (i.e., R resultant vector is the sum of the horizontal component of the quadriceps and patellar tendon force) at the following joint angles: you need to provide a diagram showing the vector and its components for each part. a1) Θ = 160 degrees, a2) Θ = 90 degrees. NOTE: USE ONLY TRIGNOMETRIC FUNCTIONS (SIN/TAN/COS, NO LAW OF COSINES, NO COMPLICATED ALGEBRAIC EQUATIONS OR ANYTHING ELSE, ETC. Question A has 2 parts!

Answer 2

Question

Chapter 13, Problem 1OQ

To determine

With relation to the air outside the balloon, the effect on the temperature, pressure and density of the air inside the balloon when it is heated by a flame

Expert Solution & Answer

Answer to Problem 1OQ

Solution:

Temperature is higher inside the balloon
Pressure is same inside and outside balloon
Density is lower

Explanation of Solution

A. Temperature is higher inside the balloon. This is the basic principle on which a hot-air balloon works. As the air inside the balloon gets heated by the flame, it rises upwards through the surrounding air, which is colder.

B. Pressure is the same inside and outside the balloon. Otherwise, the balloon would inflate or deflate. The density of air particles is lower because of the high temperature inside the balloon. This should lower the pressure. But because of the higher energy of these particles, they are moving faster and even this smaller quantity ends up exerting the pressure required to balance the outside pressure.

C. Density is lower. Because of the higher temperature of the air, the density is lower.

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Answer 3

Question

Chapter 13, Problem 1OQ

To determine

With relation to the air outside the balloon, the effect on the temperature, pressure and density of the air inside the balloon when it is heated by a flame

Expert Solution & Answer

Answer to Problem 1OQ

Solution:

Temperature is higher inside the balloon
Pressure is same inside and outside balloon
Density is lower

Explanation of Solution

A. Temperature is higher inside the balloon. This is the basic principle on which a hot-air balloon works. As the air inside the balloon gets heated by the flame, it rises upwards through the surrounding air, which is colder.

B. Pressure is the same inside and outside the balloon. Otherwise, the balloon would inflate or deflate. The density of air particles is lower because of the high temperature inside the balloon. This should lower the pressure. But because of the higher energy of these particles, they are moving faster and even this smaller quantity ends up exerting the pressure required to balance the outside pressure.

C. Density is lower. Because of the higher temperature of the air, the density is lower.

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Answer 4

Question

Chapter 13, Problem 1OQ

To determine

With relation to the air outside the balloon, the effect on the temperature, pressure and density of the air inside the balloon when it is heated by a flame

Expert Solution & Answer

Answer to Problem 1OQ

Solution:

Temperature is higher inside the balloon
Pressure is same inside and outside balloon
Density is lower

Explanation of Solution

A. Temperature is higher inside the balloon. This is the basic principle on which a hot-air balloon works. As the air inside the balloon gets heated by the flame, it rises upwards through the surrounding air, which is colder.

B. Pressure is the same inside and outside the balloon. Otherwise, the balloon would inflate or deflate. The density of air particles is lower because of the high temperature inside the balloon. This should lower the pressure. But because of the higher energy of these particles, they are moving faster and even this smaller quantity ends up exerting the pressure required to balance the outside pressure.

C. Density is lower. Because of the higher temperature of the air, the density is lower.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 13, Problem 1OQ

To determine

With relation to the air outside the balloon, the effect on the temperature, pressure and density of the air inside the balloon when it is heated by a flame

Expert Solution & Answer

Answer to Problem 1OQ

Solution:

Temperature is higher inside the balloon
Pressure is same inside and outside balloon
Density is lower

Explanation of Solution

A. Temperature is higher inside the balloon. This is the basic principle on which a hot-air balloon works. As the air inside the balloon gets heated by the flame, it rises upwards through the surrounding air, which is colder.

B. Pressure is the same inside and outside the balloon. Otherwise, the balloon would inflate or deflate. The density of air particles is lower because of the high temperature inside the balloon. This should lower the pressure. But because of the higher energy of these particles, they are moving faster and even this smaller quantity ends up exerting the pressure required to balance the outside pressure.

C. Density is lower. Because of the higher temperature of the air, the density is lower.

Answer 6

Chapter 13, Problem 1OQ

To determine

With relation to the air outside the balloon, the effect on the temperature, pressure and density of the air inside the balloon when it is heated by a flame

Expert Solution & Answer

Answer to Problem 1OQ

Solution:

Temperature is higher inside the balloon
Pressure is same inside and outside balloon
Density is lower

Explanation of Solution

A. Temperature is higher inside the balloon. This is the basic principle on which a hot-air balloon works. As the air inside the balloon gets heated by the flame, it rises upwards through the surrounding air, which is colder.

B. Pressure is the same inside and outside the balloon. Otherwise, the balloon would inflate or deflate. The density of air particles is lower because of the high temperature inside the balloon. This should lower the pressure. But because of the higher energy of these particles, they are moving faster and even this smaller quantity ends up exerting the pressure required to balance the outside pressure.

C. Density is lower. Because of the higher temperature of the air, the density is lower.

Answer 7

Chapter 13, Problem 1OQ

To determine

With relation to the air outside the balloon, the effect on the temperature, pressure and density of the air inside the balloon when it is heated by a flame

Answer 8

Expert Solution & Answer

Answer to Problem 1OQ

Solution:

Temperature is higher inside the balloon
Pressure is same inside and outside balloon
Density is lower

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

Explanation of Solution

A. Temperature is higher inside the balloon. This is the basic principle on which a hot-air balloon works. As the air inside the balloon gets heated by the flame, it rises upwards through the surrounding air, which is colder.

B. Pressure is the same inside and outside the balloon. Otherwise, the balloon would inflate or deflate. The density of air particles is lower because of the high temperature inside the balloon. This should lower the pressure. But because of the higher energy of these particles, they are moving faster and even this smaller quantity ends up exerting the pressure required to balance the outside pressure.

C. Density is lower. Because of the higher temperature of the air, the density is lower.