FOUND.OF COLLEGE CHEMISTRY
FOUND.OF COLLEGE CHEMISTRY
15th Edition
ISBN: 9781119234555
Author: Hein
Publisher: WILEY
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Chapter 13, Problem 20PE

(a)

Interpretation Introduction

Interpretation:

Mass of water in 125 gAlCl36H2O has to be calculated.

Concept Introduction:

Mass percent is one of the commonly used concentration terms to determine concentration of any species. The expression for mass percent of any species present in sample is as follows:

  Mass percent=(Mass of speciesMass of sample)(100 %)

(a)

Expert Solution
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Answer to Problem 20PE

Mass of water in 125 gAlCl36H2O is 55.98 g.

Explanation of Solution

Molecular mass of AlCl3 is 133.34 g/mol and H2O is 18.02 g/mol. Expression to calculate total mass of water is calculated as follows:

  Total mass of water=(Number of molecules of water)(Mass of water)        (1)

Substitute 6 for number of molecules of water and 18.02 g/mol for mass of water in equation (1).

  Total mass of water=(6)(18.02 g/mol)=108.12 g/mol

The formula to calculate mass percent of water is as follows:

  Mass percent of water=(Total mass of H2O(molecular mass of AlCl3)+(total mass of H2O))(100 %)        (2)

Substitute 108.12 g/mol for total mass of H2O and 133.34 g/mol for molecular mass of AlCl3 in equation (2).

  Mass percent of water=(108.12 g/mol(133.34 g/mol)+(108.12 g/mol))(100 %)=(108.12 g/mol241.46 g/mol)(100 %)=44.78 %

Hence, mass percent of water in AlCl36H2O is 44.78 %.

The formula to calculate mass of water is as follows:

  Mass of water=(Mass of AlCl36H2O)(Mass percent of water)100 %        (3)

Substitute 125 g for mass of AlCl36H2O and 44.78 % for mass percent of water in equation (3).

  Mass of water=(125 g)(44.78 %)100 %=55.98 g

Hence, mass of water in 125 g AlCl36H2O is 55.98 g.

(b)

Interpretation Introduction

Interpretation:

Mass of anhydrous compound of AlCl36H2O has to be calculated.

Concept Introduction:

Compound that does not contain any water molecule is termed as anhydrous compound. Mass of anhydrous compound is calculated as follows:

  Mass of anhydrous compound=(Mass of hydrated compond)(Mass of water)

(b)

Expert Solution
Check Mark

Answer to Problem 20PE

Mass of anhydrous compound is 69.02 g.

Explanation of Solution

The expression used to calculate mass of anhydrous compound is as follows:

  Mass of anhydrous salt=(Mass of AlCl36H2O)(Mass of water)        (4)

Substitute 125 g for AlCl36H2O and 55.98 g for mass of water.

  Mass of anhydrous salt=125 g55.98 g=69.02 g

Hence, mass of anhydrous compound is 69.02 g.

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Chapter 13 Solutions

FOUND.OF COLLEGE CHEMISTRY

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