
Concept explainers
Interpretation:
The products formed when 1,3-butadiene reacts with the given reagents are to be determined.
Concept introduction:
Hydrogenation with platinum as a catalyst is a reducing agent and can be used to convert unsaturated carbohydrates to saturated hydrocarbons.
Potassium permanganate oxidizes hydrocarbons to carbon dioxide. Also hot alkaline KMnO4 oxidatively cleaves
Alkenes react with halides and undergo substitution reaction where halides replace the double bonds. The product stereochemistry is dependent on the stereochemistry of the reactant alkene.
Conjugated dienes undergo both 1,2- and 1,4-electrophilic addition.
The 1,2 – addition to a diene is the addition of electrophile to the carbon designated as 1 and the nucleophile to the carbon designated as 2 as shown below. But the positions of carbons as 1 and 2 are not according to the IUPAC numbering of the molecule but as a conjugated diene. The mechanism is similar with 1,4-addition.
The mechanism of 1,2 addition and 1,4-addition of hydro halogenation is given below.

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Chapter 13 Solutions
ORGANIC CHEMISTRY-ETEXT REG ACCESS
- From the following potentials, calculate the activity of Cl- in saturated KCl. E0 (calomel electrode)= 0.268 V E (calomel electrode, saturated KCl)= 0.241 Varrow_forwardCalculate the voltage of each of the following cells. a) Fe(s)/Fe2+ (1.55 x 10-2 M)//Cu2+ (6.55 x 10-3 M)/Cu(s) b) Pt, H2 (0.255 bar)/HCl (4.55 x 10-4 M), AgCl (sat'd)/Ag Fe2+ +2e- = Fe E0= -0.44 V Cu2+ + 2e- = Cu E0= 0.337 V Ag+ + e- = Ag E0= 0.799 V AgCl(s) + e- = Ag(s) + Cl- E0= 0.222 V 2H+ + 2e- = H2 E0= 0.000 Varrow_forwardA solution contains 0.097 M Ce3+, 1.55x10-3 M Ce4+, 1.55x10-3 M Mn2+, 0.097 M MnO4-, and 1.00 M HClO4 (F= 9.649 x 104 C/mol). a) Write a balanced net reaction that can occur between species in this solution. b) Calculate deltaG0 and K for the reaction. c) Calculate E and deltaG for the conditions given. Ce4+ + e- = Ce3+ E0= 1.70 V MnO4- + 8H+ + 5e- = Mn2+ + 4H2O E0= 1.507 Varrow_forward
- 1. Provide a step-by-step mechanism for formation of ALL STEREOISOMERS in the following reaction. Na HCO3 (Sodium bicarbonate, baking soda) is not soluble in CH2Cl2. The powder is a weak base used to neutralize strong acid (pKa < 0) produced by the reaction. Redraw the product to show the configuration(s) that form at C-2 and C-4. Br2 OH CH2Cl2 Na* HCO3 Br HO OH + Na Br +arrow_forward2. Specify the solvent and reagent(s) required to carry out each of the following FGI. If two reagent sets must be used for the FGI, specify the solvent and reagent(s) for each reagent set. If a reaction cannot be carried out with reagents (sets) class, write NP (not possible) in the solvent box for reagent set #1. Use the letter abbreviation for each solvent; use a number abbreviation for reagent(s). Solvents: CH2Cl2 (A); H₂O (B); Reagents: HBr (1); R₂BH (6); H2SO4 (2); CH3OH (C); Br₂ (3); CH3CO₂H (D) NaHCO3 (4); Hg(OAc)2 (5); H₂O2/HO (7); NaBH4 (8) Reagent Set #1 Reagent Set #2 FGI + enant OH Solvent Reagent(s) Solvent Reagent(s)arrow_forwardGermanium (Ge) is a semiconductor with a bandgap of 2.2 eV. How could you dope Ge to make it a p-type semiconductor with a larger bandgap? Group of answer choices It is impossible to dope Ge and have this result in a larger bandgap. Dope the Ge with silicon (Si) Dope the Ge with gallium (Ga) Dope the Ge with phosphorus (P)arrow_forward
- Which of the following semiconductors would you choose to have photons with the longest possible wavelengths be able to promote electrons to the semiconductor's conduction band? Group of answer choices Si Ge InSb CdSarrow_forwardWhich of the following metals is the only one with all of its bands completely full? Group of answer choices K Na Ca Alarrow_forward2. Specify the solvent and reagent(s) required to carry out each of the following FGI. If two reagent sets must be used for the FGI, specify the solvent and reagent(s) for each reagent set. If a reaction cannot be carried out with reagents (sets) class, write NP (not possible) in the solvent box for reagent set #1. Use the letter abbreviation for each solvent; use a number abbreviation for reagent(s). Solvents: CH2Cl2 (A); Reagents: H₂O (B); CH3CO₂H (D) NaHCO3 (4); Hg(OAc)2 (5); HBr (1); R₂BH (6); H2SO4 (2); CH3OH (C); Br₂ (3); H₂O₂ / HO- (7); NaBH4 (8) Reagent Set #1 Reagent Set #2 FGI OH - α-α Br + enant Solvent Reagent(s) Solvent Reagent(s)arrow_forward
- Based on concepts from Lecture 3-5, which of the following ionic compounds should be most soluble in water? Group of answer choices MgO BeO CaO BaOarrow_forwardFrom an energy standpoint, which two process - in the correct order - are involved in the dissolving of an ionic compound crystal? Group of answer choices Water coordination to the ions followed by sublimation into the gas phase Sublimation of the crystal into gas-phase ions followed by water coordination to the ions Ion dissociation from the crystal followed by water coordination to the ions Water coordination to the ions followed by ion dissociation from the crystalarrow_forwardFor which Group 2 metal (M), is this process the most exothermic? M2+(g) + O2−(g) + CO2(g) → MO(s) + CO2(g) Group of answer choices M = Sr M = Mg M = Ca M = Baarrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
