Concept explainers
Interpretation:
The molecular orbital diagram for ground state of cyclopentadiene is to be completed; appropriate lobes are to be shaded to indicate the phase signs. HOMO and LUMO orbitals are to be labeled. Appropriate number of electrons, using straight single-barbed arrows in each level, is to be represented.
Concept introduction:
舧 Molecular orbital diagrams are used to explain the linear combination of atomic orbitals.
舧 HOMO and LUMO are types of molecular orbitals and are abbreviations for highest occupied molecular orbital and lowest unoccupied molecular orbital, respectively.
舧 Each lobe is a representation of p-orbital and each lobe has two poles, that is, shaded and non-shaded regions.
舧 The orbitals are aligned in such a way that each double bond in cyclopentadiene has the same orbitals.
舧 The lowest energy position is where all orbitals are shaded on top and clear on bottom.
舧 The second energy level has one orbital overlap.
舧 Third energy level has no orbital overlap but the two orbitals in the same alignment create similar signs through-space conjugation.
舧 Fourth energy level has no orbital overlaps or no sign changes and hence, it is the most unstable.
舧 There are two pi-bonds in cyclopentadiene, meaning 4 pi-electrons present in the system.
舧 The pi-electrons fill the lowest energy level.
Want to see the full answer?
Check out a sample textbook solutionChapter 13 Solutions
ORGANIC CHEMISTRY-ETEXT REG ACCESS
- 5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3arrow_forwardShow work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?arrow_forward13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…arrow_forward
- Hi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!arrow_forwardHi!! Please provide a solution that is handwritten. Ensure all figures, reaction mechanisms (with arrows and lone pairs please!!), and structures are clearly drawn to illustrate the synthesis of the product as per the standards of a third year organic chemistry course. ****the solution must include all steps, mechanisms, and intermediate structures as required. Please hand-draw the mechanisms and structures to support your explanation. Don’t give me AI-generated diagrams or text-based explanations, no wordy explanations on how to draw the structures I need help with the exact mechanism hand drawn by you!!! I am reposting this—ensure all parts of the question are straightforward and clear or please let another expert handle it thanks!!arrow_forward. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. < cleavage Bond A • CH3 + 26. t cleavage 2°C• +3°C• Bond C Cleavage CH3 ZC '2°C. 26. E Strongest 3°C. 2C. Gund Largest BDE weakest bond In that molecule a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest C bond Produces A Weakest Bond Most Strongest Bond Stable radical Strongest Gund produces least stable radicals b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 人 8°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. methyl radical •CH3 formed in bund A Cleavagearrow_forward
- Which carbocation is more stable?arrow_forwardAre the products of the given reaction correct? Why or why not?arrow_forwardThe question below asks why the products shown are NOT the correct products. I asked this already, and the person explained why those are the correct products, as opposed to what we would think should be the correct products. That's the opposite of what the question was asking. Why are they not the correct products? A reaction mechanism for how we arrive at the correct products is requested ("using key intermediates"). In other words, why is HCl added to the terminal alkene rather than the internal alkene?arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning