Chapter 1.3, Problem 19SSC

(a)

To determine

The volume of the box.

Answer to Problem 19SSC

The volume of the box is $7054.656{\text{cm}}^3$ .

Explanation of Solution

Given info:

Length of the box, $l=18.1\text{cm}$

Width of the box, $w=19.2\text{cm}$

Height of the box, $h=20.3\text{cm}$

Formula Used:

The expression for the volume of the box is,

  $V=l\times w\times h$

Calculation:

Substitute values in the above expression.

  $\begin{array}{c}V=\left(18.1\text{cm}\right)\left(19.2\text{cm}\right)\left(20.3\text{cm}\right)\\ =7054.656{\text{cm}}^3\end{array}$

Therefore, the volume of the box is $7054.656{\text{cm}}^3$ .

(b)

To determine

The precision in the measurement of the length or volume.

Explanation of Solution

The unit of the dimension of the box is centimeter. The dimension is measured up to tenth place of the unit. The volume of the box is measured up to thousandth place of the unit. As the number of significant figures is more in the measurement of volume than the length, so the volume of the box is measured more precisely than the length of the box.

(c)

To determine

The height of the $12$ boxes.

Answer to Problem 19SSC

The height of the $12$ boxes is $243.6\text{cm}$ .

Explanation of Solution

Given info:

Number of the boxes, $n=12$

Formula Used:

The height of the box is,

  $H=nh$

Calculation:

Substitute all the values in the above expression.

  $\begin{array}{c}H=\left(12\right)\left(20.3\text{cm}\right)\\ =243.6\text{cm}\end{array}$

Therefore, the height of the $12$ boxes is $243.6\text{cm}$ .

(d)

To determine

The precision in the measurement of the one box or 12 boxes.

Explanation of Solution

The number of significant figures in the measurement of the one or 12 boxes is same, so the precision in the measurement in the height of one box or 12 boxes is same.