Explanation Explanation To determine: The pOH and concentration of OH − ; the concentration of morphine; the value of K b . The stated reaction is, C 18 H 21 O 3 N ( a q ) + H 2 O ( l ) ⇌ C 18 H 21 O 3 NH + ( a q ) + OH − ( a q ) The value of pOH is 4.41 _ . Given The initial concentration of codeine is 1 .7 × 10 − 3 M . The pH value of reactant is 9.59 . Formula The relation between pOH and pH is, pH + pOH = 14 Where, pH is the measure of H + ions. pOH is the measure of OH − . Substitute the value of is concentration of pOH in the above equation. pH + pOH = 14 pOH = 14 − 9 .59 = 4.41 _ The stated reaction is, C 18 H 21 O 3 N ( a q ) + H 2 O ( l ) ⇌ C 18 H 21 O 3 NH + ( a q ) + OH − ( a q ) The concentration of OH − ions is 3.89 × 10 − 5 M _ . The pOH is calculated using the formula, pOH = − log 10 [ OH − ] Where, pOH is the measure of OH − ions. [ OH − ] is concentration of OH − ions. Substitute the value of pOH in the above equation. pOH = − log 10 [ OH − ] 4 .41 = − log 10 [ OH − ] [ OH − ] = 3.89 × 10 − 5 M _ The stated reaction is, C 18 H 21 O 3 N ( a q ) + H 2 O ( l ) ⇌ C 18 H 21 O 3 NH + ( a q ) + OH − ( a q ) The value of K b is 9

2nd Edition

ISBN: 9781305079243

Author: Steven S. Zumdahl, Susan A. Zumdahl

Publisher: Cengage Learning

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Chapter 13, Problem 155AE

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Interpretation: The concentration and pH of derivative of morphine (codeine) solution is given. By using these values, the value of Kb is to be calculated.

Concept introduction: The base dissociation constant Kb is the ratio of product of equilibrium concentrations of product to the equilibrium concentration of reactant base.

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Chapter 13, Problem 154AE

Chapter 13, Problem 156AE

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Solution Summary: The author explains how the concentration and pH of derivative of morphine (codeine) solution is given.

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