Concept explainers
The oldest artificial satellite still in orbit is Vanguard I, launched March 3, 1958. It mass is 1.60 kg. Neglecting atmospheric drag, the satellite would still be in its initial orbit, with a minimum distance from the center of Earth of 7.02 Mm and a speed at this perigee point of 8.23 km/s. For this orbit, find (a) the total energy of the satellite–Earth system and (b) the magnitude of the
(a)
The total energy of the satellite earth system.
Answer to Problem 13.79CP
The total energy of the satellite earth system is
Explanation of Solution
Given info: Mass of the satellite is
Write the expression for total energy of the satellite earth system.
Here,
Substitute
Conclusion:
Therefore, the total energy of the satellite earth system is
(b)
The magnitude of angular momentum of the satellite.
Answer to Problem 13.79CP
The magnitude of angular momentum of the satellite is
Explanation of Solution
Given info: Mass of the satellite is
Write the expression for angular momentum.
Here,
Substitute
Conclusion:
Therefore, the magnitude of angular momentum of the satellite is
(c)
The satellite’s speed and it’s distanced from the centre of the earth at apogee.
Answer to Problem 13.79CP
The satellite’s speed is
Explanation of Solution
Given info: Mass of the satellite is
Write the expression for total energy at apogee.
Here,
Write the expression for angular momentum at apogee.
Rearrange the expression for distanced from the centre of the earth at apogee.
Substitute
Rearrange the above equation to get a quadratic equation of
Substitute
Find the smaller roots of the above equation.
Substitute
Conclusion:
Therefore, the satellite’s speed is
(d)
The semi major axis of its orbit.
Answer to Problem 13.79CP
The semi major axis of its orbit is
Explanation of Solution
Given info: Mass of the satellite is
Write the expression for length of major axis.
Substitute
Conclusion:
Therefore, the semi major axis of its orbit is
(e)
The period of the satellite.
Answer to Problem 13.79CP
The period of the satellite is
Explanation of Solution
Given info: Mass of the satellite is
Write the expression for time period.
Substitute
Conclusion:
Therefore, the period of the satellite is
Want to see more full solutions like this?
Chapter 13 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
- air is pushed steadily though a forced air pipe at a steady speed of 4.0 m/s. the pipe measures 56 cm by 22 cm. how fast will air move though a narrower portion of the pipe that is also rectangular and measures 32 cm by 22 cmarrow_forwardNo chatgpt pls will upvotearrow_forward13.87 ... Interplanetary Navigation. The most efficient way to send a spacecraft from the earth to another planet is by using a Hohmann transfer orbit (Fig. P13.87). If the orbits of the departure and destination planets are circular, the Hohmann transfer orbit is an elliptical orbit whose perihelion and aphelion are tangent to the orbits of the two planets. The rockets are fired briefly at the depar- ture planet to put the spacecraft into the transfer orbit; the spacecraft then coasts until it reaches the destination planet. The rockets are then fired again to put the spacecraft into the same orbit about the sun as the destination planet. (a) For a flight from earth to Mars, in what direction must the rockets be fired at the earth and at Mars: in the direction of motion, or opposite the direction of motion? What about for a flight from Mars to the earth? (b) How long does a one- way trip from the the earth to Mars take, between the firings of the rockets? (c) To reach Mars from the…arrow_forward
- No chatgpt pls will upvotearrow_forwarda cubic foot of argon at 20 degrees celsius is isentropically compressed from 1 atm to 425 KPa. What is the new temperature and density?arrow_forwardCalculate the variance of the calculated accelerations. The free fall height was 1753 mm. The measured release and catch times were: 222.22 800.00 61.11 641.67 0.00 588.89 11.11 588.89 8.33 588.89 11.11 588.89 5.56 586.11 2.78 583.33 Give in the answer window the calculated repeated experiment variance in m/s2.arrow_forward
- How can i solve this if n1 (refractive index of gas) and n2 (refractive index of plastic) is not known. And the brewsters angle isn't knownarrow_forward2. Consider the situation described in problem 1 where light emerges horizontally from ground level. Take k = 0.0020 m' and no = 1.0001 and find at which horizontal distance, x, the ray reaches a height of y = 1.5 m.arrow_forward2-3. Consider the situation of the reflection of a pulse at the interface of two string described in the previous problem. In addition to the net disturbances being equal at the junction, the slope of the net disturbances must also be equal at the junction at all times. Given that p1 = 4.0 g/m, H2 = 9.0 g/m and Aj = 0.50 cm find 2. A, (Answer: -0.10 cm) and 3. Ay. (Answer: 0.40 cm)please I need to show all work step by step problems 2 and 3arrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University