An electrolysis cell for aluminum production operates at 5.0 V and a current of 1.0 × 10 5 A. Calculate the number of kilowatt-hours of energy required to produce 1 metric ton ( 1.0 × 10 3 kg) of aluminum. ( 1 kWh = 3.6 × 10 6 J and 1 J = 1 C V.)
An electrolysis cell for aluminum production operates at 5.0 V and a current of 1.0 × 10 5 A. Calculate the number of kilowatt-hours of energy required to produce 1 metric ton ( 1.0 × 10 3 kg) of aluminum. ( 1 kWh = 3.6 × 10 6 J and 1 J = 1 C V.)
Solution Summary: The author calculates the number of kilowatt-hours of energy required to produce 1 metric ton of aluminum in an electrolytic cell operating at a given current and potential difference.
An electrolysis cell for aluminum production operates at 5.0 V and a current of
1.0
×
10
5
A. Calculate the number of kilowatt-hours of energy required to produce 1 metric ton (
1.0
×
10
3
kg) of aluminum. (
1
kWh
=
3.6
×
10
6
J and
1
J
=
1
C V.)
Definition Definition Process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state.
9:27 AM Tue Mar 4
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Problem 64 of 15
#63%
Submit
Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product
structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s).
Be sure to account for all bond-breaking and bond-making steps.
0:0
0:0
:0:
N.
:0:
:O
:0:
H
H.
:0:
Select to Add Arrows
O
:0:
H
O
:0:
0:0.
S.
H
Select to Add Arrows
S
:0:
:0:
H
H
Order the following organic reactions by relative rate. That is, select '1' next to the reaction that will have the fastest initial rate, select '2' next to the reaction
that will have the next fastest initial rate, and so on. If two reactions will have very similar initial rates, you can select the same number next to both.
If a reaction will have zero or nearly zero initial rate, don't select a number and check the box in the table instead.
Note: the "Nu" in these reactions means "a generic nucleophile."
ملی
CI
:Nu
2
он
3
H
Reaction
Relative Rate
(Choose one) ▼
Nu
:CI:
zero or nearly zero
Nu
:Nu
bi
(Choose one)
zero or nearly zero
: Nu
لی
Nu
:H
(Choose one)
zero or nearly zero
9:12 AM Tue Mar 4
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Problem 38 of 15
Submit
Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow
the arrows to draw the product formed in this reaction or mechanistic step(s).
Include all lone pairs and charges as appropriate. Ignore inorganic byproducts.
Br2
FeBrз
H
(+)
Br:
H
: Br----FeBr3
く
a
SU
00
nd
e
Chapter 13 Solutions
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