Chapter 13, Problem 13.62SP

Interpretation Introduction

Interpretation:

The preparation of $\text{165}\text{mL}$ of a $\text{0}\text{.0268}$ M solution of benzoic acid ( ${\text{C}}_{\text{7}}{\text{H}}_{\text{6}}{\text{O}}_{\text{2}}$ ) in chloroform ( ${\text{CHCl}}_{\text{3}}$ ) needs to be explained.

Concept introduction:

The molarity of solution is defined as number of moles of solute in 1L of the solution. It is mathematically represented as follows:

$M=\frac{n}{V\left(L\right)}$

Here, n is number of moles and V is volume of solution in L.