Chapter 13, Problem 13.55P

Interpretation Introduction

Interpretation:

Molecular mass of unknown gas has to be calculated.

Concept Introduction:

Graham’s law suggests that the rate of diffusion or effusion of gases varies inversely to the square root of its molar mass. Mathematically it can also be stated as,

  $\frac{{\text{Rate}}_{\text{A}}}{{\text{Rate}}_{\text{B}}}={\left(\frac{M_{\text{B}}}{M_{\text{A}}}\right)}^{1/2}$

Here

$M_{\text{B}}$ represent molar mass of gas B.

$M_{\text{A}}$ represent molar mass of gas A.

${\text{Rate}}_{\text{A}}$ represent rate of effusion of gas A.

${\text{Rate}}_{\text{B}}$ represent rate of effusion of gas B.