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Reaction of 2-methylpropanoic acid
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- Nitriles, R–=C≡N, undergo a hydrolysis reaction when heated with aqueous acid. What is the structure of the compound produced by hydrolysis of propanenitrile, CH3CH2C≡N, if it has IR absorptions from 2500–3100 cm-1 and at 1710 cm-1, and has M+=74?arrow_forwardCompound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forwardThe following sequence of steps converts (R)-2-octanol to (S)-2-octanol. Propose structural formulas for intermediates A and B, specify the configuration of each, and account for the inversion of configuration in this sequence.arrow_forward
- 3-Chlorocyclopropene, on treatment with AgBF4, gives a precipitate of AgCl and a stable solution of a product that shows a single 1H NMR absorption at 11.04 δ. What is a likely structure for the products, and what is its relation to HĂ¼ckel’s rule?arrow_forwardReaction of 2-methylpropanoic acid [(CH3)2CHCO2H] with SOCl2 followed by 2-methylpropan-1-ol forms X. X has a molecular ion at 144 and IR absorptions at 2965, 2940, and 1739 cm-1. Propose a structure for X.arrow_forwardTreatment of 2-methylpropanenitrile [(CH3)2CHCN] with CH3CH2CH2MgBr, followed by aqueous acid, affords compound V, which has molecular formula C7H14O. V has a strong absorption in its IR spectrum at 1713 cm−1, and gives the following 1H NMR data: 0.91 (triplet, 3 H), 1.09 (doublet, 6 H), 1.6 (multiplet, 2 H), 2.43 (triplet, 2 H), and 2.60 (septet, 1 H) ppm. What is the structure of V? We will learn about this reaction in Chapter 20.arrow_forward
- Reaction of (CH3)3CCHO with (C6H5)3P=C(CH3)OCH3, followed by treatment with aqueous acid, affords R (C7H14O). R has a strong absorption in its IR spectrum at 1717 cm−1 and three singlets in its 1H NMR spectrum at 1.02 (9 H), 2.13 (3 H), and 2.33 (2 H) ppm. What is the structure of R? We will learn about this reaction in Chapter 18.arrow_forward: Treatment of (CHa)CHCH(OH)CH,CH3 with TSOH affords two products (M and N) with molecular formula CgH12. The 'H NMR spectra of M and N are given below. Propose structures for M and N and draw a mechanism to explain their formation. 1H NMR of M 3H 1H NMR of N 3H 3H 3 H 1H 3 H 2 H 2H 2H 8 7 6 4 1 0 9 8. 2 1 ppm ppm 4.arrow_forwardThe treatment of (CH3)2C = CHCH2Br with H2O forms B (molecular formula C5H10O) as one of the products. Determine the structure of B from its H NMR and IR spectra.arrow_forward
- Compounds Y and Z are isomers with the molecular formula C10H12O. The IR spectrum of each compound shows a strong absorption band near 1710 cm−1 . The 1H NMR spectra of Y and Z are given below. Propose structures for Y and Z.arrow_forwardTreatment of (CH3)2CHCH(OH)CH2CH3 with TsOH affords two products(M and N) with molecular formula C6H12. The 1H NMR spectra of M and Nare given below. Propose structures for M and N, and draw a mechanismto explain their formation.arrow_forwardAs reaction of (CH3)2CO with LIC≡CH followed by H2O affords compound D, which has a molecular ion in its mass spectrum at 84 and prominent absorptions in its IR spectrum at 3600−3200, 3303, 2938, and 2120 cm−1. D shows the following 1H NMR spectral data: 1.53 (singlet, 6 H), 2.37 (singlet, 1 H), and 2.43 (singlet, 1 H) ppm. What is the structure of D?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning