Chapter 13, Problem 13.52AP

Interpretation Introduction

(a)

Interpretation:

The structure of compound A with molecular formula ${\text{C}}_{\text{6}}{\text{H}}_{\text{14}}{\text{O}}_{\text{2}}$ is to be stated using the IR and NMR data of the compound.

Concept introduction:

Many nuclei and electrons have spin, due to this spin magnetic moment arises. The energy of this magnetic moment depends on the orientation of the applied magnetic field. In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. Tetramethylsilane (TMS) is taken as reference.

Interpretation Introduction

(b)

Interpretation:

The structure of compound B with molecular formula ${\text{C}}_5{\text{H}}_{\text{10}}\text{O}$ is to be stated using the IR and NMR data of the compound.

Concept introduction:

Many nuclei and electrons have spin, due to this spin magnetic moment arises. The energy of this magnetic moment depends on the orientation of the applied magnetic field. In NMR spectroscopy, every nucleus has a spin. There is an angular momentum related to the spin. The difference between its resonance frequency and that of the reference standard is known as the chemical shift of a nucleus. Tetramethylsilane (TMS) is taken as reference.