Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition) - Standalone book
Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition) - Standalone book
12th Edition
ISBN: 9780321908445
Author: Karen C. Timberlake
Publisher: PEARSON
Question
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Chapter 13, Problem 13.51UTC
Interpretation Introduction

Interpretation:

Chiral: Molecules that are non-superimposable to their mirror image, has no symmetry either point of symmetry, line of symmetry or plane of symmetry. It has a chiral carbon; chiral carbon is that carbon which is attached to four different groups is said to be a chiral carbon, or chiral center.

Achiral: Molecules whose mirror images are superimposable to each other. They have symmetry.

Concept introduction:

Simple rule to identify chiral center: It is that tetrahedral bonded carbon, where all four substituents are different. This carbon is also known as stereocenter.

Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition) - Standalone book, Chapter 13, Problem 13.51UTC , additional homework tip  1

Expert Solution & Answer
Check Mark

Answer to Problem 13.51UTC

Solution:

  (a) Glycerol: achiral

  (b) Monosodium glutamate: Chiral carbon

Explanation of Solution

  (a)

Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition) - Standalone book, Chapter 13, Problem 13.51UTC , additional homework tip  2

Indicated carbon is connected with two identical groups, so it is achiral carbon.

  (b)

Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition) - Standalone book, Chapter 13, Problem 13.51UTC , additional homework tip  3

Monosodium glutamate (MSG)

Indicated carbon in connected with four different groups/atoms as indicated, so it is chiral carbon.

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Chapter 13 Solutions

Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition) - Standalone book

Ch. 13.2 - Prob. 13.11QAPCh. 13.2 - Prob. 13.12QAPCh. 13.2 - Identify the chiral carbon in each of the...Ch. 13.2 - Prob. 13.14QAPCh. 13.2 - Prob. 13.15QAPCh. 13.2 - Prob. 13.16QAPCh. 13.2 - Prob. 13.17QAPCh. 13.2 - Prob. 13.18QAPCh. 13.2 - Prob. 13.19QAPCh. 13.2 - Prob. 13.20QAPCh. 13.3 - Prob. 13.21QAPCh. 13.3 - Prob. 13.22QAPCh. 13.3 - Prob. 13.23QAPCh. 13.3 - Prob. 13.24QAPCh. 13.3 - Prob. 13.25QAPCh. 13.3 - Prob. 13.26QAPCh. 13.3 - Prob. 13.27QAPCh. 13.3 - Prob. 13.28QAPCh. 13.3 - Prob. 13.29QAPCh. 13.3 - Prob. 13.30QAPCh. 13.4 - What are the kind and number of atoms in the ring...Ch. 13.4 - What are the kind and number of atoms in the ring...Ch. 13.4 - Prob. 13.33QAPCh. 13.4 - Prob. 13.34QAPCh. 13.4 - Prob. 13.35QAPCh. 13.4 - Identify each of the following as the a or ß...Ch. 13.5 - Prob. 13.37QAPCh. 13.5 - Prob. 13.38QAPCh. 13.5 - Prob. 13.39QAPCh. 13.5 - Prob. 13.40QAPCh. 13.6 - Prob. 13.41QAPCh. 13.6 - Prob. 13.42QAPCh. 13.6 - Prob. 13.43QAPCh. 13.6 - Prob. 13.44QAPCh. 13.6 - Prob. 13.45QAPCh. 13.6 - Prob. 13.46QAPCh. 13.7 - Describe the similarities and differences in the...Ch. 13.7 - Prob. 13.48QAPCh. 13.7 - Prob. 13.49QAPCh. 13.7 - Prob. 13.50QAPCh. 13 - Prob. 13.51UTCCh. 13 - Prob. 13.52UTCCh. 13 - Prob. 13.53UTCCh. 13 - Prob. 13.54UTCCh. 13 - Prob. 13.55UTCCh. 13 - Prob. 13.56UTCCh. 13 - Prob. 13.57AQAPCh. 13 - Prob. 13.58AQAPCh. 13 - Prob. 13.59AQAPCh. 13 - Prob. 13.60AQAPCh. 13 - Prob. 13.61AQAPCh. 13 - Prob. 13.62AQAPCh. 13 - Prob. 13.63AQAPCh. 13 - Prob. 13.64AQAPCh. 13 - Prob. 13.65AQAPCh. 13 - Prob. 13.66AQAPCh. 13 - Prob. 13.67AQAPCh. 13 - Prob. 13.68AQAPCh. 13 - Prob. 13.69AQAPCh. 13 - Prob. 13.70AQAPCh. 13 - Prob. 13.71CQCh. 13 - Prob. 13.72CQCh. 13 - 13.77 Gentiobiose is found in saffron. (13.4,...Ch. 13 - Prob. 13.74CQ
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