Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 13, Problem 13.28CTP
To determine
Find the factor of safety.
Find the inclination of the critical plane that has the minimum factor of safety.
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An excavation is to be made in purely cohesive soil deposit having c = 20 kN/m² and unit weight
= 16 kN/m³. The depth to which the vertical sides of the excavation will remain stable without side
supports will be:
The soil condition in the field is as follows:
c = 20 kN/m²,
= 20°, Y = 20 kN/m³
The maximum
depth of unsupported excavation is
m.
.
Qus
Chapter 13 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Prob. 13.4PCh. 13 - Prob. 13.5PCh. 13 - Prob. 13.6PCh. 13 - Prob. 13.7PCh. 13 - Prob. 13.8PCh. 13 - Prob. 13.9PCh. 13 - Prob. 13.10P
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - Prob. 13.15PCh. 13 - Prob. 13.16PCh. 13 - Prob. 13.17PCh. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Prob. 13.20PCh. 13 - Prob. 13.21PCh. 13 - Prob. 13.22PCh. 13 - Prob. 13.23PCh. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27CTPCh. 13 - Prob. 13.28CTPCh. 13 - Prob. 13.29CTP
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- An excavation is made with a vertical face in a clay soil which has C = 50 KN/m2, y = 18 KN/m³. The maximum depth of excavation so that the excavation is stable if S = 0.261 n for = 90⁰arrow_forwardThe figure below shows a proposed site where an excavation will be made. The 12 ft layer of sand will be removed, so that the top of the 30 ft normally consolidated clay layer will be exposed (Assume that changes in GWT do not affect γt of clay). a. Assume that the water-table location remains the same during excavation. Compute the σ, σ′v, and u values at the middle of the clay layer before and after the excavation b. Assuming 1-D conditions, compute how much the clay layer will deform due to this excavation, in inches. Specify whether this is settlement or heavearrow_forwardA cut slope is to be excavated in saturated clay with sides rising at an angle a = 55° to the horizontal, as shown below B Saturated Clay Ysat = 115 Ib/ft Unconfined Compressive Strength q,= 1000 Ib/ft? a = 55°, B = 35° H. B A a. The depth H of the excavation for a factor of safety of 1 when considering the trial failure plane AC is ft. b. The depth H of the excavation for a factor of safety of 1 when considering the most critical failure plane is ft.arrow_forward
- The excavation shown below will be made on the clay for the construction of a highway. Potential Slope stability analysis is required on the slip plane. The ground is silty clay and c '= 18 kPa,' '= 20o and water = 100 kPa. At point a If the shear stress is 60 kPa, calculate the safety coefficient for this point.arrow_forwardFor Questions A and B a temporary earth support wall is supporting a 25 ft excavation. A. Neatly draw the active soil pressure diagram, based on Rankine Theory, behind the wall and show the maximum pressure at the bottom of the temporary wall after completion of the excavation. Also indicate the location of the theoretical slip (failure) plane and its angle from the vertical. The soil is a saturated clay with properties as follows: gsat = 132 pcf, f = 19o c = 450 psf B. Use table 5.5 in the textbook and repeat problem 2 for a medium-dense gravely-sand with the following properties shown on the table: gin-situ = 120 pcf, f = 34o c = 0 psfarrow_forwardA cut slope was excavated in sand. The slope is shown in following attachment . To find the properties of the sand, representative samples were taken for the soil and tested in atriaxial apparatus. A consolidated drained triaxial test was conducted. The result is given below:Chamber pressure = 103 kN/m2Deviator stress at failure = 234.6 kN/m2We know the unit weight of the sand is 16 kN/m3.Use the ordinary method of slices (use 7 slices) and estimate the factor of safety against sliding forshown slip surface and comment on the calculated factor of safety.Please note that:1. The figure is not in scale. You may resketch it in scale and calculate the factor of safety2. The slip surface is circular and passes through the toe of the embankmentarrow_forward
- Complete and correct solution pleasearrow_forwardProperties of soil and concrete 4m O = 30° Cohesion =0 Coefficient of base friction = 0. 50 Soil's ultimiate bearing capacity= 425 kNm deoncrete = 23.6 kN /m? Use Ronkine's theory considering no evoson and future excavation would happen in the Soil. %3D 12 D. %3D a) Determine the location of the active force from the base. b) Determine the total noirmal force reaction of soil at the boser c) Determine FS SLIDING . d) Determine FSauturning o e) Determine FSpering.arrow_forward2 An unsupported excavation is made to the maximum possible depth in a clay soil having Y₁ = 18 kN/m³, c = 100 kN/m², p = 30°. The active earth pressure, according to Rankine's theory, at the base level of the excavation is (a) 115.47 kN/m² (b) 54.36 kN/m² (c) 27.18 kN/m² (d) 13.0 kN/m²arrow_forward
- Please solve all the three a,b,c as soon as possible. A trench is to be excavated in a clay soil with γsat =20 kN/m3 and su=15 kPa.(a) Determine the theoretical maximum depth of thetrench without lateral support.(b) It was decided to use a bentonite slurry of unitweight γf to fill the trench as excavation proceeds.Show that the theoretical maximum depth of thetrench is Hcr = 4su / γsat - γf where γsat is the saturatedunit weight of the soil and su is the undrainedshear strength.(c) How much deeper can the trench be excavated byusing a bentonite slurry of γf= 11 kN/m3?arrow_forwardAt a foundation site, there is an impervious stratum at 30 m and water table at 3 m below ground surface. If Ysat. -18.84 kN/m³, then what can be the maximum depth of excavation without the possibility of a blow? [Take Yw = 9.81 kN/m³] 3m X = Depth of cutting 30 marrow_forwardfind passive and active pressurearrow_forward
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