Fundamentals of Geotechnical Engineering (MindTap Course List)
5th Edition
ISBN: 9781305635180
Author: Braja M. Das, Nagaratnam Sivakugan
Publisher: Cengage Learning
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Chapter 13, Problem 13.14P
To determine
Find the factor of safety.
Find the type of failure circle.
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A site consists of a 12 m thick saturated clay deposit underlain by bedrock. The clay has ??=20.0????/??3and ????=40????/??2 . If an excavation is to be made at a slope angle ??=25° to a depth of 10.0 m, what would be the factor of safety FSs? What type of failure circle would you expect?
Geotechnical engineering
Q.4
A 40° slope is excavated to a depth of 8 m in a deep layer of saturated clay having
strength parameters c = 58 kN/m², Ø = 0, and y = 18 kN/m³. Determine the factor of
safety for the trial failure surface shown in Fig. 4
Q.5
Figure 5 shows an infinite slope with H = 32 ft and the groundwater table coinciding
Chapter 13 Solutions
Fundamentals of Geotechnical Engineering (MindTap Course List)
Ch. 13 - Prob. 13.1PCh. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Prob. 13.4PCh. 13 - Prob. 13.5PCh. 13 - Prob. 13.6PCh. 13 - Prob. 13.7PCh. 13 - Prob. 13.8PCh. 13 - Prob. 13.9PCh. 13 - Prob. 13.10P
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - Prob. 13.15PCh. 13 - Prob. 13.16PCh. 13 - Prob. 13.17PCh. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Prob. 13.20PCh. 13 - Prob. 13.21PCh. 13 - Prob. 13.22PCh. 13 - Prob. 13.23PCh. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27CTPCh. 13 - Prob. 13.28CTPCh. 13 - Prob. 13.29CTP
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- An excavation is made with a vertical face in a clay soil which has C_{u} = 50kN /(m ^2) gamma_{1} = 18kN / (m^3) and S_{n} = 0.261. The maximum depth of a stable excavation will be nearly?arrow_forwardAnswer Q13 to Q 15 based on following description A cutting in a saturated clay is inclined at a slope 1 vert:1.2 horizontal and has a vertical height of 10.0 m. The bulk unit weight of the soil is 18 kN/m³ and its undrained cohesion is 35 kN/m³. Undrained friction angle, -0. Area of slip mass = 51.2 m², d= 7 m r=12m 2m 1 W 10m FoS of a slope along a circular slip surface is given by; cular F = Wd Calculate the arc length along the slip surface, La a-964.8 m O b. 16.8 m O c. 114.0 m O d. 8.4 m d=5m 1.2arrow_forwardIn a clayey soil having 50 kN/m² as unit cohesion and 18 kN/m³ as unit weight, an excavation is made with a vertical face. Taking Taylor's stability number as 0.261, what is the maximum depth of excavation so that the vertical face remains stable?arrow_forward
- 3. In a large field with a flat surface, an excavation will take place. According to the drilling works, no groundwater was encountered, and a homogeneous cohesionless soil has been found throughout the excavation depth. As a result of the experiments, the internal friction angle of the relevant soil was found to be 24°, and the dry and saturated unit weights were 17 kN/m³ and 19.2 kN/m², respectively. According to the information given, what is the inclination of the steepest slope that can be excavated in the area?arrow_forwardAn excavation is to be made in purely cohesive soil deposit having c = 20 kN/m² and unit weight = 16 kN/m³. The depth to which the vertical sides of the excavation will remain stable without side supports will be:arrow_forwardThe figure below shows a proposed site where an excavation will be made. The 12 ft layer of sand will be removed, so that the top of the 30 ft normally consolidated clay layer will be exposed (Assume that changes in GWT do not affect γt of clay). a. Assume that the water-table location remains the same during excavation. Compute the σ, σ′v, and u values at the middle of the clay layer before and after the excavation b. Assuming 1-D conditions, compute how much the clay layer will deform due to this excavation, in inches. Specify whether this is settlement or heavearrow_forward
- A vertical cut has been made into a homogeneous soil as depicted in the figure. What should the depth of the cut (H) be in metres so that the factor of safety for the failure plane shown is equal to 1.5? The failure plane is at an angle of 30° from the horizontal direction and the ground water level is below this plane. Assume undrained conditions for this question.arrow_forwardCENTER OF FAILURE CIRCLE soil 1 unit weight = 16 kN/m3 c = 20 kPa ' = 25 deg soil 2 unit weight = 18 kN/m3 c = 30 kPa = 35 deg Scale 1 cm = 2m Figure shows an embankment consisting of two soils with the given soil properties. There is no ground water table in the vicinity. (a) Calculate the factor of safety using the Ordinary Method of Slices (b) Assuming a factor of safety of 1.5, perform one iteration to calculate factor of safety using the Bishop?s Method of Slicesarrow_forwardA vertical cut is made in a purely cohesive soil with a volumetric weight of ym = 1.90 cohesion of 4.0 ton/m2 and angle of internal friction of $=0°. These parameters were obtained in a consolidated rapid test. Calculate the maximum height at which it can be temporarily withoutsupport. H? EXCAVACIÓN ARCILLA Ym 1.90 ton/m³ C = 4.00 ton/m² Excavation= Excavación Clay= Arcilla = 0°arrow_forward
- An excavation is to be made in a layer of clay which is 10 m thick and underlain by a sandstone formation. The water table is at the ground surface and the saturated unit weight of clay is 21 kN/m³. The water level in a piezometer installed in the sandstone rises 2.5 m above the ground surface. Draw a representative sketch of the problem and calculate the depth of excavation that can be reached without an upheave of the bottom of excavation.arrow_forwardPlease answer 15.15arrow_forwardA site consists of a 12 m thick saturated clay deposit underlain by bedrock. The clay has ?=20.0?N/?3and ??=40?N/?2 . If an excavation is to be made at a slope angle ?=25° to a depth of 10.0 m, what would be the factor of safety FSs? What type of failure circle would you expect? (Please open the image in a new tab if need be, Thank you)arrow_forward
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