Chemistry Principles And Practice
3rd Edition
ISBN: 9781305295803
Author: David Reger; Scott Ball; Daniel Goode
Publisher: Cengage Learning
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Chapter 13, Problem 13.14QE
Interpretation Introduction
Interpretation:
The mechanism of a reaction has to be defined. How the mechanism relates to the order of the reaction has to be explained.
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Solution
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Use retrosynthetic analysis to suggest two paths to synthesize 2-methyl-3-hexanol using the Grignard reaction. (Click and drag
the appropriate image to the correct position in the reactions.)
Route 1
Aldehyde 1
or
+98
Aldehyde 2
Route 2
Q6
+100
Solved in 1 attempt
Q7
+95
Solved in 2 attempts
Q8
+98
Unlimited attempts
possible
+
+
Grignard 1
OH
H3O+
Grignard 2
Answer Bank
Q9
+90
MgBr
Unlimited attempts
possible
CH3CH2CH2MgBr
Q10
Unlimited attempts
Q11
?
?
+100
in 1 attempt
2-methyl-3-hexanol
CH3CH2MgBr
H
H
о
H
Attempt 3
2) (4 pt) After the reaction was completed, the student collected the following data. Crude
product data is the data collected after the reaction is finished, but before the product
is purified. "Pure" product data is the data collected after attempted purification using
recrystallization.
Student B's data:
Crude product data
"Pure"
product data
after
recrystallization
Crude mass: 0.93 g grey solid
Crude mp: 96-106 °C
Crude % yield:
Pure mass: 0.39 g white solid
Pure mp: 111-113 °C
Pure % yield:
a) Calculate the crude and pure percent yields for the student's reaction.
b) Summarize what is indicated by the crude and pure melting points.
Don't used hand raiting
Chapter 13 Solutions
Chemistry Principles And Practice
Ch. 13 - Prob. 13.1QECh. 13 - Prob. 13.2QECh. 13 - What is the difference between the integrated and...Ch. 13 - Prob. 13.4QECh. 13 - Explain why half-lives are not normally used to...Ch. 13 - Derive an expression for the half-life of a...Ch. 13 - Prob. 13.7QECh. 13 - Prob. 13.8QECh. 13 - Prob. 13.9QECh. 13 - Prob. 13.10QE
Ch. 13 - Prob. 13.11QECh. 13 - Prob. 13.12QECh. 13 - Prob. 13.13QECh. 13 - Prob. 13.14QECh. 13 - Prob. 13.15QECh. 13 - Prob. 13.16QECh. 13 - Prob. 13.17QECh. 13 - Prob. 13.18QECh. 13 - Prob. 13.19QECh. 13 - Prob. 13.20QECh. 13 - Prob. 13.21QECh. 13 - Prob. 13.22QECh. 13 - Nitrogen monoxide reacts with chlorine to form...Ch. 13 - Prob. 13.24QECh. 13 - Prob. 13.25QECh. 13 - Prob. 13.26QECh. 13 - Prob. 13.27QECh. 13 - Prob. 13.28QECh. 13 - Prob. 13.29QECh. 13 - Prob. 13.30QECh. 13 - Prob. 13.31QECh. 13 - Prob. 13.32QECh. 13 - Prob. 13.33QECh. 13 - Write a rate law for NO3(g) + O2(g) NO2(g) +...Ch. 13 - Prob. 13.35QECh. 13 - Prob. 13.36QECh. 13 - Prob. 13.37QECh. 13 - Rate data were obtained at 25 C for the following...Ch. 13 - Prob. 13.39QECh. 13 - Prob. 13.40QECh. 13 - Prob. 13.41QECh. 13 - Prob. 13.42QECh. 13 - Prob. 13.43QECh. 13 - Prob. 13.44QECh. 13 - Prob. 13.45QECh. 13 - Prob. 13.46QECh. 13 - Prob. 13.47QECh. 13 - Prob. 13.48QECh. 13 - When formic acid is heated, it decomposes to...Ch. 13 - Prob. 13.50QECh. 13 - The half-life of tritium, 3H, is 12.26 years....Ch. 13 - Prob. 13.52QECh. 13 - Prob. 13.53QECh. 13 - Prob. 13.54QECh. 13 - Prob. 13.55QECh. 13 - Prob. 13.56QECh. 13 - The decomposition of ozone is a second-order...Ch. 13 - Prob. 13.58QECh. 13 - Prob. 13.59QECh. 13 - Prob. 13.60QECh. 13 - A reaction rate doubles when the temperature...Ch. 13 - Prob. 13.62QECh. 13 - Prob. 13.63QECh. 13 - Prob. 13.64QECh. 13 - Prob. 13.65QECh. 13 - The activation energy for the decomposition of...Ch. 13 - Prob. 13.67QECh. 13 - Prob. 13.68QECh. 13 - Prob. 13.69QECh. 13 - Prob. 13.70QECh. 13 - Prob. 13.71QECh. 13 - Prob. 13.72QECh. 13 - Prob. 13.73QECh. 13 - Prob. 13.74QECh. 13 - Prob. 13.75QECh. 13 - Prob. 13.76QECh. 13 - Prob. 13.77QECh. 13 - Prob. 13.78QECh. 13 - Prob. 13.79QECh. 13 - Prob. 13.80QECh. 13 - The gas-phase reaction of nitrogen monoxide with...Ch. 13 - Prob. 13.82QECh. 13 - Prob. 13.83QECh. 13 - A catalyst reduces the activation energy of a...Ch. 13 - Prob. 13.85QECh. 13 - Prob. 13.86QECh. 13 - Prob. 13.87QECh. 13 - Prob. 13.88QECh. 13 - Prob. 13.89QECh. 13 - Prob. 13.90QECh. 13 - Prob. 13.91QECh. 13 - Prob. 13.92QECh. 13 - Prob. 13.93QECh. 13 - Prob. 13.94QECh. 13 - Prob. 13.95QECh. 13 - Prob. 13.96QECh. 13 - Prob. 13.98QECh. 13 - Prob. 13.99QE
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- A DEPT NMR spectrum is shown for a molecule with the molecular formula of C5H12O. Draw the structure that best fits this data. 200 180 160 140 120 100 一盆 00 40 8- 20 ppm 0 Qarrow_forwardDon't used hand raitingarrow_forwardShown below is the major resonance structure for a molecule. Draw the second best resonance structure of the molecule. Include all non-zero formal charges. H. H. +N=C H H H Cl: Click and drag to start drawing a structure. : ? g B S olo Ar B Karrow_forward
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