Chapter 13, Problem 121E

Interpretation Introduction

Interpretation:

The concentration of the stock solution of ${\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$ and ${\text{CaCl}}_{\text{2}}$ after the reaction is to be calculated.

Concept Introduction:

Molarity of a solution is defined as

$\text{Molarity=}\frac{\text{moles of solute}}{\text{volume of solution in litres}}$

The moles $\left(n\right)$ are defined as the ratio of mass to the molar mass.

$n=\frac{\text{Mass}}{\text{Molar mass}}$

The molarity of a stock solution can be determined as

${\text{M}}_{\text{1}}{\text{V}}_1={\text{M}}_{\text{2}}{\text{V}}_{\text{2}}$

Here ${\text{M}}_{\text{1}}$ is the molarity of a stock solution, ${\text{V}}_{\text{1}}$ is the volume of stock solution; ${\text{M}}_{\text{2}}$ is the molarity of diluted solution and ${\text{V}}_{\text{2}}$ is the volume of diluted solution