The pressure at which 95 % of the Oxygen molecules dissociate is to be calculated. Concept introduction: The equilibrium constant K describes the ratio of the reactant to the product on the equilibrium conditions in terms of molar concentration. The equilibrium constant depends upon temperature. Law of mass action is applicable on the equilibrium reactions. The Le Chatelier’s principle states that the addition of the reactants shifts the equilibrium to the right while the addition of product shifts the equilibrium to the left at constant temperature. The dissociation of the species is denotes by the symbol α . To determine: The pressure at which 95 % of the Oxygen molecules dissociate at the constant temperature.
The pressure at which 95 % of the Oxygen molecules dissociate is to be calculated. Concept introduction: The equilibrium constant K describes the ratio of the reactant to the product on the equilibrium conditions in terms of molar concentration. The equilibrium constant depends upon temperature. Law of mass action is applicable on the equilibrium reactions. The Le Chatelier’s principle states that the addition of the reactants shifts the equilibrium to the right while the addition of product shifts the equilibrium to the left at constant temperature. The dissociation of the species is denotes by the symbol α . To determine: The pressure at which 95 % of the Oxygen molecules dissociate at the constant temperature.
Solution Summary: The author explains that the equilibrium constant K describes the ratio of the reactant to the product on equilibrium conditions in terms of molar concentration.
Interpretation: The pressure at which
95% of the Oxygen molecules dissociate is to be calculated.
Concept introduction: The equilibrium constant
K describes the ratio of the reactant to the product on the equilibrium conditions in terms of molar concentration.
The equilibrium constant depends upon temperature.
Law of mass action is applicable on the equilibrium reactions.
The Le Chatelier’s principle states that the addition of the reactants shifts the equilibrium to the right while the addition of product shifts the equilibrium to the left at constant temperature.
The dissociation of the species is denotes by the symbol
α.
To determine: The pressure at which
95% of the Oxygen molecules dissociate at the constant temperature.
(11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the
molecule depicted below.
Bond B
Bond A
Bond C
a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in
appropriate boxes.
Weakest
Bond
Strongest
Bond
b. (4pts) Consider the relative stability of all cleavage products that form when bonds A,
B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B,
and C are all carbon radicals.
i. Which ONE cleavage product is the most stable? A condensed or bond line
representation is fine.
ii. Which ONE cleavage product is the least stable? A condensed or bond line
representation is fine.
c. (5pts) Use principles discussed in lecture, supported by relevant structures, to
succinctly explain the why your part b (i) radical is more stable than your part b(ii)
radical. Written explanation can be no more than one-two succinct sentence(s)!
Chapter 13 Solutions
Lab Manual for Zumdahl/Zumdahl/DeCoste¿s Chemistry, 10th Edition
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell