Concept explainers
Identify A and B, isomers of molecular formula
Want to see the full answer?
Check out a sample textbook solutionChapter 12C Solutions
ORG CHEM CONNECT CARD
Additional Science Textbook Solutions
Basic Chemistry
Chemistry: The Molecular Nature of Matter
Organic Chemistry
General, Organic, and Biological Chemistry (3rd Edition)
General, Organic, and Biological Chemistry - 4th edition
Principles of Chemistry: A Molecular Approach (3rd Edition)
- Ascaridole is a natural product that has been used to treat intestinal worms. Explain why the two methyls on the isopropyl group in ascaridole appear in its 1H-NMR spectrum as four lines of equal intensity, with two sets of two each separated by 7 Hz.arrow_forwardFollowing are three compounds with the molecular formula C4H8O2 and three 1H-NMR spectra. Assign each compound its correct spectrum and assign all signals to their corresponding hydrogens. (1) (2) (3)arrow_forward3-Bromo-1-phenyl-1-propene shows a complex NMR spectrum in which the vinylic proton at C2 is coupled with both the C1 vinylic proton (J = 16 Hz) and the C3 methylene protons (J = 8 Hz). Draw a tree diagram for the C2 proton signal, and account for the fact that a five-line multiplet is observed.arrow_forward
- 2) Compound C gave the following proton NMR signals: a) singlet,1.22 ppm, 6H; b) Triplet, 1.85 ppm, 2H, J = 7 Hz; c) triplet, 2.83 ppm, 2H, J = 7 Hz; d) singlet, 7.02 ppm, 4H. Sketch the proton NMR spectrum of compound C and assign the chemical shifts to the protons of the compounds.arrow_forward1Compound 1 has molecular formula C7H16. It shows three signals in the 1H-NMR spectrum, one at 0.85 ppm, one at 1.02 ppm, and one at 1.62 ppm. The relative integrals of these three signals are 6, 1, and 1, respectively. Compound 2 has molecular formula C7H14. It shows three signals in the 1H-NMR spectrum, one at 0.98 ppm, one at 1.36 ppm, and one at 1.55 ppm. The relative integrals of these three signals are 3, 2, and 2, respectively. Propose structures for compounds 1 and 2, explaining how you reach your conclusion.arrow_forwardCompound A, with molecular formula C4H9Cl, shows two signals in its 13C NMR spectrum. Compound B, an isomer of compound A, shows four signals, and in the proton-coupled mode, the signal farthest downfield is a doublet. Identify compounds A and Barrow_forward
- OH D آمد کو Compound A = Compound B = Compound C = Compound D = A Compound E = Compound F = Br OH How many different signals would you expect to see in the 1H NMR of the given compounds? (i.e. different chemical shifts)? B E C Z-I H F Harrow_forwardWhat is the structure of an unknown compound with molecular formula C6H15N that gives the following 1H NMR absorptions: 0.9 (singlet, 1 H), 1.10 (triplet, 3 H), 1.15 (singlet, 9 H), and 2.6 (quartet, 2 H) ppm?arrow_forwardWhat is the structure of the compound in the following ¹H-NMR spectrum with the molecular formula C9H10O₂? Relative integration is shown. HO₂C CO₂H CO₂H CHO CO₂H PPM 2arrow_forward
- Compound 1 has molecular formula C7H16. It shows three signals in the 1H-NMR spectrum, one at 0.85 ppm, one at 1.02 ppm, and one at 1.62 ppm. The relative integrals of these three signals are 6, 1, and 1, respectively. Compound 2 has molecular formula C7H14. It shows three signals in the 1H-NMR spectrum, one at 0.98 ppm, one at 1.36 ppm, and one at 1.55 ppm. The relative integrals of these three signals are 3, 2, and 2, respectively. Propose structures for compounds 1 and 2, explaining how you reach your conclusion.arrow_forwardCompound 1 has molecular formula C6H12. It shows three signals in the 1H-NMR spectrum, one at 0.96 ppm, one at 2.03 ppm, and one at 5.33 ppm. The relative integrals of these three signals are 3, 2, and 1, respectively. Compound 2 has molecular formula C7H15Br. It shows two signals in the 1H-NMR spectrum, one at 1.08 ppm and one at 1.59 ppm. The relative integrals of these two signals are 3 and 2, respectively. Propose structures for compounds 1 and 2, explaining how you reach your conclusion.arrow_forward14. Compound B has molecular formula C9H12. It shows five signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.22 ppm, a septet of integral 1 at 2.86 ppm, a singlet of integral 1 at 5.34 ppm, a doublet of integral 2 at 6.70 ppm, and a doublet of integral 2 at 7.03 ppm. The 13C-NMR spectrum of B shows six unique signals (23.9, 34.0, 115.7, 128.7, 148.9, and 157.4). Identify B and explain your reasoning.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning