(a)
Interpretation:
The product for the given set of reactions should be identified.
Concept introduction:
Alcohol: It is one type of
Base: They are substance that gives
Leaving group: it is a fragment that leaves substrate with a pair of electrons via heterolytic bond cleavage.
Nucleophile: donates pair of electrons to positively charged substrate resulting in the formation of
Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.
Carbocation: carbon atom bears positive charged species with three bonds is called Carbocation and it plays vital intermediate in
Carbocation’s are classified in to three types as primary, secondary and tertiary depending on the number of carbon atoms which is attached to the ionized carbon.
Tertiary carbocation is more stable than secondary carbocation, secondary carbocation is more stable than the primary carbocation as shown below.
(b)
Interpretation:
The product for the given set of reactions should be identified.
Concept introduction:
Alcohol: It is one type of functional group in organic chemistry in which carbon is singly bonded to one
Base: They are substance that gives
Leaving group: it is a fragment that leaves substrate with a pair of electrons via heterolytic bond cleavage.
Nucleophile: donates pair of electrons to positively charged substrate resulting in the formation of chemical bond.
Elimination Reaction: It is just reverse reaction of addition where substituent from the given molecule is removed via E1 (the reaction depends only on the substrate involved in the reaction) or E2 (the reaction depends on both of the substituents in the reaction) mechanism.
Carbocation: carbon atom bears positive charged species with three bonds is called Carbocation and it plays vital intermediate in organic synthesis. Carbocation migratory aptitude is mainly depends on the stability of the carbocation. This type of carbocation undergoes inter or intra molecule reactions and it form more stable product this type of rearrangement called carbocation rearrangement.
Carbocation’s are classified in to three types as primary, secondary and tertiary depending on the number of carbon atoms which is attached to the ionized carbon.
Tertiary carbocation is more stable than secondary carbocation, secondary carbocation is more stable than the primary carbocation as shown below.
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Chapter 12 Solutions
ORGANIC CHEMISTRY-NEXTGEN+BOX (2 SEM.)
- H2SO4 (cat.), H₂O 100 °C NH₂arrow_forwardX Draw the major products of the elimination reaction below. If elimination would not occur at a significant rate, check the box under the drawing area instead. ది www. Cl + OH Elimination will not occur at a significant rate. Click and drag to start drawing a structure.arrow_forwardNonearrow_forward
- 1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forwardNonearrow_forwardIV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forward
- Do the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forwardPredict and draw the product of the following organic reaction:arrow_forwardNonearrow_forward
- Redraw the molecule below as a skeletal ("line") structure. Be sure to use wedge and dash bonds if necessary to accurately represent the direction of the bonds to ring substituents. Cl. Br Click and drag to start drawing a structure. : ☐ ☑ Parrow_forwardK m Choose the best reagents to complete the following reaction. L ZI 0 Problem 4 of 11 A 1. NaOH 2. CH3CH2CH2NH2 1. HCI B OH 2. CH3CH2CH2NH2 DII F1 F2 F3 F4 F5 A F6 C CH3CH2CH2NH2 1. SOCl2 D 2. CH3CH2CH2NH2 1. CH3CH2CH2NH2 E 2. SOCl2 Done PrtScn Home End FA FQ 510 * PgUp M Submit PgDn F11arrow_forwardNonearrow_forward
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