At time t = 0 a skier leaves the end of a ski jump with a speed of υ 0 ft / s at an angle α with the horizontal (see the accompanying figure). The skier lands 259 ft down the incline 2.9 s later. (a) Approximate υ 0 to the nearest f t / s and α to the nearest degree. [ N ote: Use g = 32 ft / s 2 as the acceleration due to gravity.] (b) Use a CAS or a calculating utility with a numerical integration capability to approximate the distance traveled by the skier.
At time t = 0 a skier leaves the end of a ski jump with a speed of υ 0 ft / s at an angle α with the horizontal (see the accompanying figure). The skier lands 259 ft down the incline 2.9 s later. (a) Approximate υ 0 to the nearest f t / s and α to the nearest degree. [ N ote: Use g = 32 ft / s 2 as the acceleration due to gravity.] (b) Use a CAS or a calculating utility with a numerical integration capability to approximate the distance traveled by the skier.
At time
t
=
0
a skier leaves the end of a ski jump with a speed of
υ
0
ft
/
s
at an angle
α
with the horizontal (see the accompanying figure). The skier lands 259 ft down the incline 2.9 s later.
(a) Approximate
υ
0
to the nearest
f
t
/
s
and
α
to the nearest degree. [Note:
Use
g
=
32
ft
/
s
2
as the acceleration due to gravity.]
(b) Use a CAS or a calculating utility with a numerical integration capability to approximate the distance traveled by the skier.
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
How would i solve this. More info is that b =1 but it might be better to solve this before making the substitution
Let m(t) be a continuous function with a domain of all real numbers. The table below shows some of the values of m(t) .
Assume the characteristics of this function are represented in the table.
t
-3 -2 8 11
12
m(t) -7 6
3
-9
0
(a) The point (-3, -7) is on the graph of m(t). Find the corresponding point on the graph of the transformation y = -m(t) + 17.
(b) The point (8, 3) is on the graph of m(t). Find the corresponding point on the graph of the transformation y =
-m (−t) .
24
(c) Find f(12), if we know that f(t) = |m (t − 1)|
f(12) =
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