Chapter 12.6, Problem 30E

To determine

To find:the actual distance for $8.5inches$ when its scale is $1inch:50miles$ .

Answer to Problem 30E

the actual distance for $8.5inches$ is $425miles$ when its scale is $1inch:50miles$ .

Explanation of Solution

Given : thescaleprovided in the question,

  $1inch:50miles$

Calculation : to find the actual distance, by using the scale first we put the value on 1 inch then multiply it.

  $1inch:50miles$

So, $1inch=50miles$

  $\begin{array}{l}8.5inch=8.5·50miles\text{ [substitue]}\\ 8.5inch=425miles\text{ [multiply]}\end{array}$

Hence, the actual distance for $8.5inches$ is $425miles$ when its scale is $1inch:50miles$ .