Chapter 12.5, Problem 9MCQ

To determine

To find: The mean median mode and range of their practice times.

Answer to Problem 9MCQ

The mean median mode and range of $7,8,7,7\text{and}12$

Explanation of Solution

Given information:

The given central frequency tendency table is $759746108578731215138$ .

Calculation:

Consider the central frequency tendency.

Mean: the mean is sum of the data divided by the number of data

  $\begin{array}{c}=\frac{7+5+9+4+6+10+8+5+7+8+7+3+12+15+13+8}{17}\\ =\frac{134}{17}\\ =7.88\end{array}$

Median: the median is the middle value in the data set

  $\boxed{345567777888910121315}$

Median $7$

Mode: The mode is the data item that occurs the most items

The values $7$ occur four times the given data set $\left(1\right)$ the mode is $7$ .

Range: the difference between greatest and least data values

  $\begin{array}{c}Range=15-3\\ =12\end{array}$

The mean is the best measure to describe the practice.

Therefore, the mean median mode and range of $7,8,7,7\text{and}12$ .