Explanation Given Information: The provided expression is: 3 log a 5 − 1 2 log a 9 Here, a > 0 and a ≠ 1 . Formula used: If x , y and b are positive real numbers, where b ≠ 1 , then following holds true. Quotient Rule of the logarithm: log b x y = log b x − log b y Power Rule of the logarithm: log b x r = r log b x Product Rule of the logarithm: log b x y = log b x + log b y Calculation: The provided expression is: 3 log a

18th Edition

ISBN: 9781323910528

Author: Lial

Publisher: PEARSON C

See similar textbooks

Videos

Question

Chapter 12.4, Problem 32E

To determine

To calculate: The single logarithm expression of the expression 3loga5−12loga9 by using properties of logarithm, here, a>0 and a≠1.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 12.4, Problem 31E

Chapter 12.4, Problem 33E

Students have asked these similar questions

1.2.9. (-) What is the minimum number of trails needed to decompose the Petersen graph? Is there a decomposition into this many trails using only paths?

1.2.7. (-) Prove that a bipartite graph has a unique bipartition (except for interchang- ing the two partite sets) if and only if it is connected.

Sx. KG A3 is collection of Countin uous function on a to Polgical Which separates Points Srem closed set then the toplogy onx is the weak toplogy induced by the map fx. Prove that using dief speParts Point If B closed and x&B in X then for some xеA fx(x) € fa(B). If (π Xx, prodect) is prodect space KEA S Prove s. BxXx (πh Bx) ≤ πTx B x Prove is an A is finte = (πT. Bx) = πT. Bå KEA XEA

Chapter 12 Solutions

INTEGRATED REV.F/BEG.+INT.ALG.W/ACC.>C<

Ch. 12.1 - Prob. 1E Ch. 12.1 - Prob. 2E Ch. 12.1 - Prob. 3E Ch. 12.1 - Prob. 4E Ch. 12.1 - Prob. 5E Ch. 12.1 - Prob. 6E Ch. 12.1 - Prob. 7E Ch. 12.1 - Prob. 8E Ch. 12.1 - Prob. 9E Ch. 12.1 - If the function is one-to-one, find its inverse....

Knowledge Booster

$Algebra$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.

The single logarithm expression of the expression 3 log a 5 − 1 2 log a 9 by using properties of logarithm, here, a > 0 and a ≠ 1 .

Solution Summary: The author explains how to calculate the single logarithm expression of the expression 3mathrmlog_a5-

Videos

To calculate: The single logarithm expression of the expression 3loga5−12loga9 by using properties of logarithm, here, a>0 and a≠1.

Want to see the full answer?

Chapter 12 Solutions

The single logarithm expression of the expression 3 log a 5 − 1 2 log a 9 by using properties of logarithm, here, a &gt; 0 and a ≠ 1 .

Solution Summary: The author explains how to calculate the single logarithm expression of the expression 3mathrmlog_a5-

Videos

To calculate: The single logarithm expression of the expression 3loga5−12loga9 by using properties of logarithm, here, a>0 and a≠1.

Want to see the full answer?

Chapter 12 Solutions

The single logarithm expression of the expression 3 log a 5 − 1 2 log a 9 by using properties of logarithm, here, a > 0 and a ≠ 1 .