Solve the vector initial-value problem for y t by integrating and using the initial conditions to find the constants of integration . y ″ t = 12 t 2 i − 2 t j , y 0 = 2 i − 4 j, y ′ 0 = 0
Solve the vector initial-value problem for y t by integrating and using the initial conditions to find the constants of integration . y ″ t = 12 t 2 i − 2 t j , y 0 = 2 i − 4 j, y ′ 0 = 0
Solve the vector initial-value problem for
y
t
by integrating and using the initial conditions to find the constants of integration.
y
″
t
=
12
t
2
i
−
2
t
j
,
y
0
=
2
i
−
4
j,
y
′
0
=
0
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
The velocity of a particle moving in the plane has components
dx
= 12t – 312 and-
dt
dy
= In(1 + (t – 4)*)
dt
At time t = 0, the position of the particle is (-13, 5). At time t= 2, the object is at point P with
x-coordinate 3.
Find the speed of the particle and its acceleration vector at t= 2.
Find the y-coordinate of P.
Write an equation for the tangent line to the curve at P.
Find the integrating factor for
dy — 2хy dx — х dх.
А. e1-2у
1
В.
1-2у
C. el+2y
1
D. ;
1+2y
Solve the initial value problem for r as a vector
function of t.
Differential equation:
Initial conditions:
d²r
di²
r(0) 10i+ 10j + 10k and
dr
dt
= -(i+j+ k)
= 0
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