The compound that is more soluble in benzene than in water should be identified. Concept introduction: Like dissolves like principle: ‘Like dissolves like’ principle says that polar compounds including ionic compound should be more soluble in polar solvent. Likewise, non–polar compound should be more soluble in non–polar solvent. Polar molecule: Polar molecules have large dipole moments. Non-Polar molecules: Non-polar molecules have bonded atoms with similar electronegativity results to have zero dipole moments. Solubility is the quantity of solute (solid, liquid or gas) that will dissolve in a given amount of solvent (solid, liquid or gas) at definite temperature and pressure. Solubility depends on the physical and chemical property of solvent, solute and concentration of the solution.

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Chapter 12.2, Problem 1RCF

Interpretation Introduction

Interpretation:

The compound that is more soluble in benzene than in water should be identified.

Concept introduction:

Like dissolves like principle: ‘Like dissolves like’ principle says that polar compounds including ionic compound should be more soluble in polar solvent. Likewise, non–polar compound should be more soluble in non–polar solvent.

Polar molecule: Polar molecules have large dipole moments.

Non-Polar molecules: Non-polar molecules have bonded atoms with similar electronegativity results to have zero dipole moments.

Solubility is the quantity of solute (solid, liquid or gas) that will dissolve in a given amount of solvent (solid, liquid or gas) at definite temperature and pressure. Solubility depends on the physical and chemical property of solvent, solute and concentration of the solution.

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LTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimai