General Chemistry
11th Edition
ISBN: 9781305859142
Author: Ebbing, Darrell D., Gammon, Steven D.
Publisher: Cengage Learning,
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Question
Chapter 12.2, Problem 12.2CC
Interpretation Introduction
Interpretation:
Given that compound X has stronger intermolecular force and has no dipole-dipole forces, compound Y has Hydrogen bonding, the relative solubility of the compounds X and Y in water and non-polar solvent has to be predicted and the same has to be explained.
Concept Introduction:
- The intermolecular forces are the attractive forces between the molecules of a compound.
- The three types of intermolecular forces are – London dispersion force, dipole-dipole force and Hydrogen bonding. Among these London dispersion force is the weakest one and dipole-dipole force is the strongest one.
- London dispersion forces exist in non-polar covalent compounds. Dipole-dipole forces present in polar covalent compounds. This is the force responsible for the condensation of non-polar compounds into liquids or solids under low temperature.
- Hydrogen bonding is formed in polar covalent compounds containing direct bond between Hydrogen and other high electronegativity like Fluorine, Oxygen or Nitrogen.
- The order of strength of intermolecular force is,
London dispersion force < Dipole-dipole force < Hydrogen bonding.
However London dispersion forces become stronger in case of larger molecules.
Expert Solution & Answer
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Use the expression below to
⚫ calculate its value and report it to the proper number of significant digits (you may need to
round your answer).
⚫ calculate the % error (or % relative error or % inherent error)
⚫ calculate the absolute error.
(20.54±0.02 × 0.254±0.003) / (3.21±0.05) =
Value:
% Error:
Absolute error: ± |
% (only 1 significant digit)
(only 1 significant digit)
In each case (more ductile, more brittle, more tough or resistant), indicate which parameter has a larger value.
parameter Elastic limit Tensile strength
more ductile
Strain at break Strength Elastic modulus
more fragile
more tough or resistant
None
Chapter 12 Solutions
General Chemistry
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