
(a)
Interpretation:
A multistep synthesis of the given compounds from the given starting material has to be given.
Concept introduction:
Bromination:
2-methyl propane undergoes radical bromination which yields the 2-bromo-2-methylpropane.because bromination will occur where the tertiary radical is present. (bromination reactions are more selective reaction).
Formation of
The
(b)
Interpretation:
A multistep synthesis of the given compounds from the given starting material has to be given.
Concept introduction:
Bromination:
2-methyl propane undergoes radical bromination which yields the 2-bromo-2-methylpropane.because bromination will occur where the tertiary radical is present. (bromination reactions are more selective reaction).
Oxidation of alcohol:
Alcohols reacts with hypochlorous (oxidizing agent) in the presence of acetic acid which yields the corresponding
Primary alcohols gives aldehyde, secondary alcohols gives ketone.
The alcohols reacts with acids like hydrochloric acid or hydrobromic acid, the bromine atom attacks back side of the carbon atoms which is bearing alcohol group and yields the corresponding product.
(c)
Interpretation:
A multistep synthesis of the given compounds from the given starting material has to be given.
Concept introduction:
Bromination:
2-methyl propane undergoes radical bromination which yields the 2-bromo-2-methylpropane.because bromination will occur where the tertiary radical is present. (bromination reactions are more selective reaction).
Oxidation of alcohol:
Alcohols reacts with hypochlorous (oxidizing agent) in the presence of acetic acid and yields the corresponding aldehyde and ketones.
Primary alcohols gives aldehyde, secondary alcohols gives ketone.
SN2 reaction:
The alcohols reacts with acids like hydrochloric acid or hydrobromic acid, the bromine atom attacks back side of the carbon atoms which is bearing alcohol group and yields the corresponding product.
(d)
Interpretation:
A multistep synthesis of the given compounds from the given starting material has to be given.
Concept introduction:
Bromination:
2-methyl propane undergoes radical bromination which yields the 2-bromo-2-methylpropane.because bromination will occur where the tertiary radical is present. (bromination reactions are more selective reaction).
Formation of epoxide:
The alkene can be converted to epoxide when alkene is treated with MCPBA (m-chloro perbenzoic acid)

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Chapter 12 Solutions
Organic Chemistry Study Guide and Solutions Manual, Books a la Carte Edition (8th Edition)
- + C8H16O2 (Fatty acid) + 11 02 → 8 CO2 a. Which of the above are the reactants? b. Which of the above are the products? H2o CO₂ c. Which reactant is the electron donor? Futty acid d. Which reactant is the electron acceptor? e. Which of the product is now reduced? f. Which of the products is now oxidized? 02 #20 102 8 H₂O g. Where was the carbon initially in this chemical reaction and where is it now that it is finished? 2 h. Where were the electrons initially in this chemical reaction and where is it now that it is finished?arrow_forward→ Acetyl-CoA + 3NAD+ + 1FAD + 1ADP 2CO2 + CoA + 3NADH + 1FADH2 + 1ATP a. Which of the above are the reactants? b. Which of the above are the products? c. Which reactant is the electron donor? d. Which reactants are the electron acceptors? e. Which of the products are now reduced? f. Which product is now oxidized? g. Which process was used to produce the ATP? h. Where was the energy initially in this chemical reaction and where is it now that it is finished? i. Where was the carbon initially in this chemical reaction and where is it now that it is finished? j. Where were the electrons initially in this chemical reaction and where is it now that it is finished?arrow_forwardRank each of the following substituted benzene molecules in order of which will react fastest (1) to slowest (4) by electrophilic aromatic substitution. OCH 3 (Choose one) OH (Choose one) Br (Choose one) Explanation Check NO2 (Choose one) © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Aarrow_forward
- For each of the substituted benzene molecules below, determine the inductive and resonance effects the substituent will have on the benzene ring, as well as the overall electron-density of the ring compared to unsubstituted benzene. Molecule Inductive Effects O donating O withdrawing O no inductive effects Resonance Effects Overall Electron-Density ○ donating ○ withdrawing O no resonance effects O electron-rich O electron-deficient O similar to benzene Cl O donating O withdrawing ○ donating ○ withdrawing O no inductive effects O no resonance effects O Explanation Check O electron-rich O electron-deficient similar to benzene X © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessarrow_forwardIdentifying electron-donating and For each of the substituted benzene molecules below, determine the inductive and resonance effects the substituent will have on the benzene ring, as well as the overall electron-density of the ring compared to unsubstituted benzene. Molecule Inductive Effects NH2 ○ donating NO2 Explanation Check withdrawing no inductive effects Resonance Effects Overall Electron-Density ○ donating O withdrawing O no resonance effects O donating O withdrawing O donating withdrawing O no inductive effects Ono resonance effects O electron-rich electron-deficient O similar to benzene O electron-rich O electron-deficient O similar to benzene olo 18 Ar 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forwardRank each of the following substituted benzene molecules in order of which will react fastest (1) to slowest (4) by electrophilic aromatic substitution. Explanation Check Х (Choose one) OH (Choose one) OCH3 (Choose one) OH (Choose one) © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centerarrow_forward
- Assign R or S to all the chiral centers in each compound drawn below porat bg 9 Br Brarrow_forwarddescrive the energy levels of an atom and howan electron moces between themarrow_forwardRank each set of substituents using the Cahn-Ingold-Perlog sequence rules (priority) by numbering the highest priority substituent 1.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
