ORGANIC CHEMISTRY W/ALEKS
ORGANIC CHEMISTRY W/ALEKS
6th Edition
ISBN: 9781264905430
Author: SMITH
Publisher: MCG CUSTOM
Question
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Chapter 12.10, Problem 20P
Interpretation Introduction

(a)

Interpretation: The alkene which yields the given oxidative cleavage products is to be predicted.

Concept introduction: In presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. Depending upon alkyl substituents, aldehyde or ketone is formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Interpretation Introduction

(b)

Interpretation: The alkene which yields the given oxidative cleavage products is to be predicted.

Concept introduction: In presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. Depending upon alkyl substituents aldehyde or ketone is formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Interpretation Introduction

(c)

Interpretation: The alkene which yields the given oxidative cleavage products is to be predicted.

Concept introduction: In presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. Depending upon alkyl substituents aldehyde or ketone is formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

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