Air drop A plane traveling horizontally at 80 m/s over flat ground at an elevation of 3000 m releases an emergency packet. The trajectory of the packet is given by x = 80 t , y = − 4.9 t 2 + 3000 , for t ≥ 0 , where the origin is the point on the ground directly beneath the plane at the moment of the release. Graph the trajectory of the packet and find the coordinates of the point where the packet lands.
Air drop A plane traveling horizontally at 80 m/s over flat ground at an elevation of 3000 m releases an emergency packet. The trajectory of the packet is given by x = 80 t , y = − 4.9 t 2 + 3000 , for t ≥ 0 , where the origin is the point on the ground directly beneath the plane at the moment of the release. Graph the trajectory of the packet and find the coordinates of the point where the packet lands.
Solution Summary: The author calculates the coordinates of the point where the emergency packet lands from a plane by graphing its trajectory.
Air drop A plane traveling horizontally at 80 m/s over flat ground at an elevation of 3000 m releases an emergency packet. The trajectory of the packet is given by
x
=
80
t
,
y
=
−
4.9
t
2
+
3000
,
for
t
≥
0
,
where the origin is the point on the ground directly beneath the plane at the moment of the release. Graph the trajectory of the packet and find the coordinates of the point where the packet lands.
Hi, can you guys help me with this? Thank you!
Can you guys help me calculate again the Term GPA, Combined GPA, Cumulative GPA, Transfer GPA & Combined Cumulative GPA section? It's just not right right now.
Here's the transfer totals point that I want to provide just in case you guys may ask where I get these from:
Use undetermined coefficients to find the particular solution to
y"-3y+2y=4e3
Y(t) =
Please refer below
Chapter 12 Solutions
Calculus: Early Transcendentals and MyLab Math with Pearson eText -- Title-Specific Access Card Package (3rd Edition) (Briggs, Cochran, Gillett & Schulz, Calculus Series)
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