The table of the value of y 0 to y 6 if the difference equation is y n = .75 y n − 1 + 1.25 with initial value y 0 = 2 .

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Answer 1

Question

Chapter 12.1, Problem 33E

(a)

To determine

The table of the value of y0 to y6 if the difference equation is yn=.75yn−1+1.25 with initial value y0=2.

(b)

To determine

To graph: The terms of the difference equation yn=.75yn−1+1.25 with initial value y0=2.

(c)

To determine

The value of y9 with the help of graph or table of the difference equation yn=.75yn−1+1.25 with initial value y0=2 and also determine the value of n when yn within .5 units of 5.

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(c) Suppose that all the pages are black and white, but each group of 25 con- secutive pages (1-25, 26-50, 51-75, 76-100, 101-125) must be assigned to the same printer. Each printer can be assigned 0, 25, 50, 75, 100, or 125 pages to print. How many ways are there for the 125 pages to be assigned to the five printers?

Answer 2

Question

Chapter 12.1, Problem 33E

(a)

To determine

The table of the value of y0 to y6 if the difference equation is yn=.75yn−1+1.25 with initial value y0=2.

(b)

To determine

To graph: The terms of the difference equation yn=.75yn−1+1.25 with initial value y0=2.

(c)

To determine

The value of y9 with the help of graph or table of the difference equation yn=.75yn−1+1.25 with initial value y0=2 and also determine the value of n when yn within .5 units of 5.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 3

Question

Chapter 12.1, Problem 33E

(a)

To determine

The table of the value of y0 to y6 if the difference equation is yn=.75yn−1+1.25 with initial value y0=2.

(b)

To determine

To graph: The terms of the difference equation yn=.75yn−1+1.25 with initial value y0=2.

(c)

To determine

The value of y9 with the help of graph or table of the difference equation yn=.75yn−1+1.25 with initial value y0=2 and also determine the value of n when yn within .5 units of 5.

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Answer 4

Question

Chapter 12.1, Problem 33E

(a)

To determine

The table of the value of y0 to y6 if the difference equation is yn=.75yn−1+1.25 with initial value y0=2.

(b)

To determine

To graph: The terms of the difference equation yn=.75yn−1+1.25 with initial value y0=2.

(c)

To determine

The value of y9 with the help of graph or table of the difference equation yn=.75yn−1+1.25 with initial value y0=2 and also determine the value of n when yn within .5 units of 5.

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Answer 5

Chapter 12.1, Problem 33E

(a)

To determine

The table of the value of y0 to y6 if the difference equation is yn=.75yn−1+1.25 with initial value y0=2.

(b)

To determine

To graph: The terms of the difference equation yn=.75yn−1+1.25 with initial value y0=2.

(c)

To determine

The value of y9 with the help of graph or table of the difference equation yn=.75yn−1+1.25 with initial value y0=2 and also determine the value of n when yn within .5 units of 5.

Answer 6

Chapter 12.1, Problem 33E

(a)

To determine

The table of the value of y0 to y6 if the difference equation is yn=.75yn−1+1.25 with initial value y0=2.

Answer 7

Chapter 12.1, Problem 33E

(a)

To determine

The table of the value of y0 to y6 if the difference equation is yn=.75yn−1+1.25 with initial value y0=2.

Answer 8

(b)

To determine

To graph: The terms of the difference equation yn=.75yn−1+1.25 with initial value y0=2.

Answer 9

(b)

To determine

To graph: The terms of the difference equation yn=.75yn−1+1.25 with initial value y0=2.

Answer 10

(c)

To determine

The value of y9 with the help of graph or table of the difference equation yn=.75yn−1+1.25 with initial value y0=2 and also determine the value of n when yn within .5 units of 5.

Answer 11

(c)

To determine

The value of y9 with the help of graph or table of the difference equation yn=.75yn−1+1.25 with initial value y0=2 and also determine the value of n when yn within .5 units of 5.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 12.1 - Consider the difference equation...Ch. 12.1 - Prob. 2CYU Ch. 12.1 - Prob. 1E Ch. 12.1 - Prob. 2E Ch. 12.1 - Prob. 3E Ch. 12.1 - Prob. 4E Ch. 12.1 - Prob. 5E Ch. 12.1 - For each of the difference equations in Exercises...Ch. 12.1 - Prob. 7E Ch. 12.1 - Prob. 8E

The table of the value of y 0 to y 6 if the difference equation is y n = .75 y n − 1 + 1.25 with initial value y 0 = 2 .

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The table of the value of y0 to y6 if the difference equation is yn=.75yn−1+1.25 with initial value y0=2.

To graph: The terms of the difference equation yn=.75yn−1+1.25 with initial value y0=2.

The value of y9 with the help of graph or table of the difference equation yn=.75yn−1+1.25 with initial value y0=2 and also determine the value of n when yn within .5 units of 5.

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