Exercises 4-3 deal with the Boolean algebra {0, 1} with addition, multiplication, and complement defined at the ginning of the section. In each case, use a table as in Example 8. 23. Verify the zero property. The Boolean operator ⊕ , called the XOR operator, is defined by 1 ⊕ 1 = 0 , 1 ⊕ 0 = 1 , 0 ⊕ 1 = 1 , and 0 ⊕ 0 = 0 .
Exercises 4-3 deal with the Boolean algebra {0, 1} with addition, multiplication, and complement defined at the ginning of the section. In each case, use a table as in Example 8. 23. Verify the zero property. The Boolean operator ⊕ , called the XOR operator, is defined by 1 ⊕ 1 = 0 , 1 ⊕ 0 = 1 , 0 ⊕ 1 = 1 , and 0 ⊕ 0 = 0 .
Solution Summary: The author explains that the zero property is verified using the Boolean algebra left0,1right.
Exercises 4-3 deal with the Boolean algebra {0, 1} with addition, multiplication, and complement defined at the ginning of the section. In each case, use a table as in Example 8.
23. Verify the zero property.
The Boolean operator
⊕
, called the XOR operator, is defined by
1
⊕
1
=
0
,
1
⊕
0
=
1
,
0
⊕
1
=
1
, and
0
⊕
0
=
0
.
A function is defined on the interval (-π/2,π/2) by this multipart rule:
if -π/2 < x < 0
f(x) =
a
if x=0
31-tan x
+31-cot x
if 0 < x < π/2
Here, a and b are constants. Find a and b so that the function f(x) is continuous at x=0.
a=
b= 3
Use the definition of continuity and the properties of limits to show that the function is continuous at the given number a.
f(x) = (x + 4x4) 5,
a = -1
lim f(x)
X--1
=
lim
x+4x
X--1
lim
X-1
4
x+4x
5
))"
5
))
by the power law
by the sum law
lim (x) + lim
X--1
4
4x
X-1
-(0,00+(
Find f(-1).
f(-1)=243
lim (x) +
-1 +4
35
4 ([
)
lim (x4)
5
x-1
Thus, by the definition of continuity, f is continuous at a = -1.
by the multiple constant law
by the direct substitution property
Chapter 12 Solutions
Discrete Mathematics and Its Applications ( 8th International Edition ) ISBN:9781260091991
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