AUTMOTIVE TECH, TECH MANUAL & MIND TAP
6th Edition
ISBN: 9781305383180
Author: ERJAVEC
Publisher: CENGAGE L
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Chapter 12, Problem 9RQ
To ensure proper seating of the valve, the valve seat must be.
- the correct width
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Chapter 12 Solutions
AUTMOTIVE TECH, TECH MANUAL & MIND TAP
Ch. 12 - Explain staged and continuously variable value...Ch. 12 - Define valve margin.Ch. 12 - What usually causes warpage in an aluminum cylin...Ch. 12 - What are the two ways pushrods can be checked for...Ch. 12 - Which of the following is not true of knurling? It...Ch. 12 - True False? Fiats MultiAir system relies on...Ch. 12 - To allow the engine to run on the Atkinson cycle,...Ch. 12 - Prob. 8RQCh. 12 - To ensure proper seating of the valve, the valve...Ch. 12 - When checking valve fit, contact between the valve...
Ch. 12 - If the valve face and valve seat do not contact...Ch. 12 - Many engines with WT have a phaser mounted to the...Ch. 12 - Multiple valve engines tend to be more efficient...Ch. 12 - Which of the following is not a type of valve...Ch. 12 - Which of the following statements is not true?...Ch. 12 - While discussing the reasons for resurfacing a...Ch. 12 - While inspecting the timing gears of an engine:...Ch. 12 - Technician A says that positive valve stem seals...Ch. 12 - When fitting a freshly ground valve into a freshly...Ch. 12 - Technician A says off-square springs may cause...Ch. 12 - Technician A says it is not necessary to measure...Ch. 12 - Technician A uses a 30-degree stone for topping a...Ch. 12 - While discussing the Valvetronic system:...Ch. 12 - While checking a hydraulic phaser after the...Ch. 12 - While servicing a pair of aluminum cylinder heads:...
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- A spring package with two springs and an external force, 200N. The short spring has a loin of 35 mm. Constantly looking for spring for short spring so that total compression is 35 mm (d). Known values: Long spring: Short spring:C=3.98 N/mm Lo=65mmLo=87.4mmF=c·fTotal compression is same for both spring. 200 = (3.98(c1) × 35) + (c₂ × 35) 200 = 139.3 + 35c₂ 200 - 139.3 = 35c₂ 60.7 = 35c₂ c₂ = 60.7/35 Short spring (c₂) = 1.73 N/mm According to my study book, the correct answer is 4.82N/mm What is wrong with the calculating?arrow_forwardWhat is the reason for this composition?arrow_forwardHomework: ANOVA Table for followed design B AB Dr -1 -1 1 (15.18,12) 1 -1 -1 (45.48.51) -1 1 -1 (25,28,19) 1 1 (75.75,81)arrow_forward
- 20. [Ans. 9; 71.8 mm] A semi-elliptical laminated spring is made of 50 mm wide and 3 mm thick plates. The length between the supports is 650 mm and the width of the band is 60 mm. The spring has two full length leaves and five graduated leaves. If the spring carries a central load of 1600 N, find: 1. Maximum stress in full length and graduated leaves for an initial condition of no stress in the leaves. 2. The maximum stress if the initial stress is provided to cause equal stress when loaded. [Ans. 590 MPa ; 390 MPa ; 450 MPa ; 54 mm] 3. The deflection in parts (1) and (2).arrow_forwardQ6/ A helical square section spring is set inside another, the outer spring having a free length of 35 mm greater than the inner spring. The dimensions of each spring are as follows: Mean diameter (mm) Side of square section (mm) Active turns Outer Inner Spring Spring 120 70 8 7 20 15 Determine the (1) Maximum deflection of the two springs and (2) Equivalent spring rate of the two springs after sufficient load has been applied to deflect the outer spring 60 mm. Use G = 83 GN/m².arrow_forwardQ2/ The bumper springs of a railway carriage are to be made of rectangular section wire. The ratio of the longer side of the wire to its shorter side is 1.5, and the ratio of mean diameter of spring to the longer side of wire is nearly equal to 6. Three such springs are required to bring to rest a carriage weighing 25 kN moving with a velocity of 75 m/min with a maximum deflection of 200 mm. Determine the sides of the rectangular section of the wire and the mean diameter of coils when the shorter side is parallel to the axis of the spring. The allowable shear stress is not to exceed 300 MPa and G = 84 kN/mm². Q6/ A belicalarrow_forward
- 11. A load of 2 kN is dropped axially on a close coiled helical spring, from a height of 250 mm. The spring has 20 effective turns, and it is made of 25 mm diameter wire. The spring index is 8. Find the maximum shear stress induced in the spring and the amount of compression produced. The modulus of rigidity for the material of the spring wire is 84 kN/mm². [Ans. 287 MPa; 290 mm]arrow_forwardWhat is the reason for this composition?arrow_forwardHomework: ANOVA Table for followed design B AB Dr -1 -1 1 (15.18,12) 1 -1 -1 (45.48.51) -1 1 -1 (25,28,19) 1 1 (75.75,81)arrow_forward
- S B Pin 6 mm Garrow_forwardMid-Term Exam 2024/2025 Post graduate/Applied Mechanics- Metallurgy Q1/ State the type of fault in the following case, and state the structure in which it will appear. АВСАВСВАСВАСАВСАВСarrow_forwardالثانية Babakt Momentum equation for Boundary Layer S SS -Txfriction dray Momentum equation for Boundary Layer What laws are important for resolving issues 2 How to draw. 3 What's Point about this.arrow_forward
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