BASIC BIOMECHANICS
8th Edition
ISBN: 9781259913877
Author: Hall
Publisher: RENT MCG
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Chapter 12, Problem 9AP
Using the principle of conservation of
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Chapter 12 Solutions
BASIC BIOMECHANICS
Ch. 12 - How much force must be applied by a kicker to give...Ch. 12 - A high jumper with a body weight of 712 N exerts a...Ch. 12 - What factors affect the magnitude of friction?Ch. 12 - If s between a basketball shoe and a court is...Ch. 12 - A football player pushes a 670-N blocking sled....Ch. 12 - Lineman A has a mass of 100 kg and is traveling...Ch. 12 - Prob. 7IPCh. 12 - A ball dropped on a surface from a 2-m height...Ch. 12 - A set of 20 stairs, each of 20-cm height, is...Ch. 12 - A pitched ball with a mass of 1 kg reaches a...
Ch. 12 - Identify three practical examples of each of...Ch. 12 - Prob. 2APCh. 12 - A 2-kg block sitting on a horizontal surface is...Ch. 12 - Explain the interrelationships among mechanical...Ch. 12 - Prob. 5APCh. 12 - A 108 cm, 0.73-kg golf club is swung for 0.5 s...Ch. 12 - A 6.5-N ball is thrown with an initial velocity of...Ch. 12 - Prob. 8APCh. 12 - Using the principle of conservation of mechanical...Ch. 12 - Prob. 10AP
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- Using the Michaelis-Mentan graph pictured (graphing initial velocity and PNPP concentration), identify Vmax and Km as well as possible. Then, using the Lineweaver-Burk graph (graphing 1/Vo and 1 / PNPP concentration), label the reciprocals of Vmax and Km on the graph and use them to calculate Km and Vmax.arrow_forwardUsing the above “mean-speed theorem”, calculate the average velocity of a car with constant acceleration from 0 km/hour (initial speed) to 80 km/hour (final speed) over a 5-minute period of time. average velocity over 5 minutes = 16 kilometers/hour average velocity over 5 minutes = 20 kilometers/hour average velocity over 5 minutes = 24 kilometers/hour average velocity over 5 minutes = 32 kilometers/hour average velocity over 5 minutes = 40 kilometers/hourarrow_forwardThe “mean-speed theorem” for calculating average velocity under constant acceleration, developed by Thomas Bradwardine and the Mertonian Calculators at Oxford University, is expressed algebraically as: density = weight/volume (m1)(v1) = (m2)(v2) C. (vm) = 1/2 (v0 + vf) s = (v0)(t) + 1/2 (a)(t2) velocity = distance/timearrow_forward
- From the equation of a lineweaver-burke plot, calculate Km and Vmax. Show your work and include units. The equation is y=393.4x +8.4337arrow_forwardThe “mean-speed theorem” for finding average velocity under constant acceleration, proposed by the Oxford Calculators, and demonstrated geometrically by Nicole Oresme, is expressed algebraically as: density = weight/volume (m1)(v1) = (m2)(v2) (vm) = 1/2 (v0 + vf) s = (v0)(t) + 1/2 (a)(t2) velocity = distance/timearrow_forwardA scientist was investigating if differences in the frictional work performed on a model car can change depending on its mass (in grams) and whether the car moves up or down an inclined plane. They decided to measure the amount of frictional force experienced by the model car and the distance it traveled in meters. The scientists were able to evaluate the frictional work using the following data. Mass (g) Distance (m) Force Work Done by Friction (J) car going up the incline 100 39 0.063 2.457 car going down the incline 70 39 0.2309 ? It is known that the relationship between force and distance determines the work done by friction (W+). W₁ = fd Wf work done by friction f = force d = distance Question: How much work done by friction was exerted on the car as it moved down the inclined plane? You may use a calculator. 1 2.457 9.005 11.46 16.16 PREVIOUS FINISHarrow_forward
- 72. Find J and K in the rotational system shown in Figure P4.18 to yield a 30% overshoot and a sett- ling time of 3 seconds for a step input in torque. [(Section: 4.6] 000 K FIGURE P4.18arrow_forwardAccording to Jean Buridan’s equation, the momentum or “impetus” of an 8 kilogram mass moving at 48 meters per second would be: 192 kilogram-meters per second 384 kilogram-meters per second 576 kilogram-meters per second 768 kilogram-meters per second 960 kilogram-meters per secondarrow_forwardWhen Galileo Galilei pushed a ball down an inclined plane, it had an initial velocity (vo) of 4.0 meters per second (time = 0 seconds) and a final velocity (vf) of 10.0 meters per second (time = 2 seconds). How far did the ball travel along the inclined plane in these 2 seconds? 14 meters 20 meters 28 meters 40 meters 84 metersarrow_forward
- The momentum or “impetus” of a 12 kilogram mass moving at 7 meters per second can be stopped completely by a direct collision with a 3-kilogram mass moving at a velocity of: 14 meters per second 28 meters per second 36 meters per second 63 meters per second 84 meters per secondarrow_forwardThe above computation of momentum (the term used by Isaac Newton), or “impetus” (the term used by Jean Buridan), is based on which of the following equations? (mass1)(velocity1) = (mass2)(velocity2) F = GM1M2/d2 (years)2 = (A.U.)3 vm = ½ (vo + vf)arrow_forwardIn terms of mass and acceleration, what is the equation for force?arrow_forward
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